Why does the equation for elastic collisions work like this?

In summary, the conversation discusses deriving an equation for finding the mass of gas particles using the collision of protons in a particle accelerator. The equation is m2 = (m1(v1^2 - v1'^2))/(v1-v1')^2 and it only works when both v1 and v1' are plugged in as positive values. This is due to an arithmetic error in the derivation.
  • #1
minnyveller
1
0
Hi guys. Feels dumb coming back to this but I seem to have confused myself

I was helping a friend with the problem:

You shoot protons going v=4.2e7 m/s through a particle accelerator. They collide with gas particles of an unknown mass (pretend no velocity) and all bounce back elastically at 3.9e7 m/s.

I went through the steps of deriving the equation for m2 using the two speeds as follows:

m1v1^2 = m1v1'^2 + m2v2^2
m1v1 = m1v1' + m2v2

m1v1^2 - m1v1'^2 = m2v2^2
m1v1 - m1v1' = m2v2
v1 - v1' = v2

plugging this in ^

m1v1^2 = m1v1'^2 + m2(v1-v1')^2
m1(v1^2 - v1'^2) = m2(v1-v1')^2

m1(v1^2 - v1'^2)/(v1-v1')^2 = m2

plugging in both v1 and v1' as positive values (4.2e7 and 3.9e7) you get m2=27m (which was correct)

why does it only work plugging both in as positive values? Since the proton bounces back, if 4.2e7 is positive, why is the correct answer given when 3.9e7 is put in positive?
 
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  • #2
minnyveller said:
m1v1^2 - m1v1'^2 = m2v2^2
m1v1 - m1v1' = m2v2
v1 - v1' = v2
Because you have an arithmetic error here. You should get ##v_1 + v_1' = v_2##.
 

Related to Why does the equation for elastic collisions work like this?

What is an elastic collision?

An elastic collision is a type of collision where both kinetic energy and momentum are conserved. This means that the total energy and momentum of the system remains the same before and after the collision.

Why does the equation for elastic collisions involve mass and velocity?

Mass and velocity are important factors in determining the outcome of a collision. The equation for elastic collisions takes into account the initial and final velocities of the objects, as well as their masses, to calculate the amount of kinetic energy and momentum that is conserved.

How does the angle of collision affect the outcome of an elastic collision?

The angle of collision plays a significant role in determining the final velocities of the objects involved in an elastic collision. If two objects collide head-on, their velocities will be affected differently than if they collide at an angle.

Why is the equation for elastic collisions considered an idealized scenario?

The equation for elastic collisions assumes that there is no loss of energy due to factors such as friction or deformation of the objects involved. In reality, some energy is always lost in collisions, making the equation an idealized representation of the actual outcome.

How does the equation for elastic collisions differ from the equation for inelastic collisions?

Inelastic collisions involve a loss of kinetic energy, while elastic collisions do not. This means that the equations for these two types of collisions will have different variables and outcomes. Inelastic collisions also involve the deformation of objects, which is not taken into account in the equation for elastic collisions.

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