Why Do Energy Levels in Multielectron Atoms Differ from Hydrogen?

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In summary, the lowest-l state for each n (2s, 3s, 4s, etc.) in a multielectron atom has a significantly lower energy compared to the hydrogen state with the same n, while the highest-l state for each n (2p, 3d, 4f, etc.) has a similar energy to the hydrogen state with the same n. This is due to the shielding of the inner electrons, which causes the outer electrons to behave like hydrogen electrons at each 'n'. However, the wavefunctions of the different angular momentums show that lower angular momentums are more tightly bound due to their proximity to the nucleus, while higher angular momentums behave like hydrogen atoms due to their position on
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albertsmith
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In a multielectron atom, the lowest-l state for each n (2s, 3s, 4s, etc.) is significantly lower in energy than the hydrogen state having the same n. But the highest-l state for each n (2p, 3d, 4f, etc.) is very nearly equal in energy to the hydrogen state with the same n. Can someone please explain this?
 
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Think of it this way, the hydrogen atom has Z=1. So in a multielectron system you would assume the electron furthest out would only see Z=1, because all the inner electrons are shielding the rest of the Z-1 nuclear charge. This assumption states that the outer electron's energy would behave like a hydrogen electron at each 'n' and not caring about the 'l'.

But, if you look at the wavefunctions for the different l's you notice that the 2s, 3s, 4s and so on spend a lot of time near the core. So they feel a stronger attraction than just Z=1 when they are that close to the nucleus. Whereas the larger l's spend more time on the edge of the atom where Z=1 is dominant. That is why the lower angular momentums tend to be more tightly bound and the higher angular momentums tend to behave like hydrogen atoms.
 
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This phenomenon can be explained by the concept of electron shielding. In a multielectron atom, the outer electrons are shielded from the positive charge of the nucleus by the inner electrons. This results in a decrease in the effective nuclear charge experienced by the outer electrons, making them easier to remove and therefore lower in energy.

On the other hand, the highest-l states have more electron density closer to the nucleus, which means they experience a stronger effective nuclear charge and are therefore closer in energy to the hydrogen state with the same n.

Additionally, the energy levels of electrons in a multielectron atom are also affected by the electron-electron repulsion. As the number of electrons increases, the repulsion between them increases, causing the energy levels to shift and become more complex.

Overall, the differences in energy levels between the lowest-l and highest-l states in a multielectron atom can be attributed to the interplay of electron shielding and electron-electron repulsion.
 

Related to Why Do Energy Levels in Multielectron Atoms Differ from Hydrogen?

1. What is a multielectron atom?

A multielectron atom is an atom that contains more than one electron in its outermost energy level. This is in contrast to a monoelectron atom, which has only one electron in its outermost energy level.

2. How are the electrons arranged in a multielectron atom?

In a multielectron atom, the electrons are arranged in different energy levels or orbitals. These energy levels are further divided into sublevels, each of which can hold a specific number of electrons. The exact arrangement of electrons in a multielectron atom is determined by the atom's atomic number and electron configuration.

3. How does the number of electrons affect the properties of a multielectron atom?

The number of electrons in a multielectron atom affects its properties in several ways. It determines the atom's size, reactivity, and chemical bonding behavior. The number of electrons also plays a role in determining the atom's ionization energy, or the amount of energy required to remove an electron from the atom.

4. What is the significance of the Pauli exclusion principle in multielectron atoms?

The Pauli exclusion principle states that no two electrons in an atom can have the same set of quantum numbers. In multielectron atoms, this principle explains the arrangement of electrons in different energy levels and sublevels. It also helps to explain the stability and reactivity of atoms, as well as their electronic configurations.

5. How do multielectron atoms emit light?

When electrons in a multielectron atom move from a higher energy level to a lower one, they release energy in the form of light. This is known as emission of light, and the specific wavelengths of light emitted can be used to identify the element. This process is also used in many scientific techniques, such as spectroscopy, to study the electronic structure of atoms.

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