- #1
GoghAway
Homework Statement
Willy leaves point A and Milly leaves point B, both of them are heading toward each other's starting point. They both have constant speeds, but Milly is faster, and they pass each other at noon without stopping. Milly arrives at point A at 1:00 pm, and Willy arrives at point B at 2:15 pm. At what time did they both set off?
Homework Equations
v = d / t
v = (d2 - d1) / (t2 - t1)
The Attempt at a Solution
I'm putting the data here because it's what I think the problem is telling me, but I know I could be wrong.
Willy
d = D
v = Vw
t = (14.25 hours - t1)
Vw = D / (14.25 h - t1)
Milly
d = D
v = Vm
t = (13.0 hours - t1)
Vm = D / (13.0 h - t1)
After noon
Willy
d = (D - d1)
v = Vw
t = 2.25 hours
Vw = (D - d1) / 2.25 h
Milly
d = d1
v = Vm
t = 1 hour
Vm = d1 / (1 h)
Since Milly is going faster noon, or when they meet would be after the midpoint between point A and B for her, and before the midpoint for Willy.
Since Willy's velocity is always the same:
D/(14.25 h - t1) = (D - d1)/2.25 h
D (2.25 h) = (D - d1)(14.25 h - t1)
D = ((D - d1)(14.25 h - t1)) / (2.25 h)
Since Milly's velocity is always the same:
D/(13.0 h - t1) = d1/(1 h)
D (1 h) = d1 (13.0 h - t1)
D = (d1 (13.0 h - t1)) / (1 h)
d1= (D (1 h)) / (13.0 h - t1)
I'm not sure whether I can sub what D = or what d1 = from what I have since Willy's velocity is always the same with what I have since Milly's velocity is always the same or vice versa. Either way, I don't think I know enough of the unknowns to come up with a numerical value as an answer, but I don't know how to get the information that I need.