- #1
quddusaliquddus
- 354
- 2
work out the value of the following:
1/2*sqrt[1/2 + (1/2)*(1/2)]sqrt[1/2 + (1/2)*sqrt[1/2 + (1/2)*(1/2)]]...
Any help is appreciated.
Thnak you.
what mite b of interest is the fact that it looks similar to the bottom of Viete's famous formula for pi (employing for the first time an infinite product):
[ i derived the following from cos(theta/2^1)*cos(theta/2^2)*cos(theta/2^3)...cos(theta/2^n) ]
pi=2/[sqrt[1/2]*sqrt[1/2 + (1/2)*sqrt[1/2]]sqrt[1/2 + (1/2)*sqrt[1/2 + (1/2)*sqrt[1/2]]]...]
1/2*sqrt[1/2 + (1/2)*(1/2)]sqrt[1/2 + (1/2)*sqrt[1/2 + (1/2)*(1/2)]]...
Any help is appreciated.
Thnak you.
what mite b of interest is the fact that it looks similar to the bottom of Viete's famous formula for pi (employing for the first time an infinite product):
[ i derived the following from cos(theta/2^1)*cos(theta/2^2)*cos(theta/2^3)...cos(theta/2^n) ]
pi=2/[sqrt[1/2]*sqrt[1/2 + (1/2)*sqrt[1/2]]sqrt[1/2 + (1/2)*sqrt[1/2 + (1/2)*sqrt[1/2]]]...]