What Is the Exact Value of x That Minimizes y for Positive x?

Second, this is a critical point because y' is 0 there and it is a local minimum because it is the only critical point and y goes from positive to negative as x increases. You do not need to convert it to a whole number. The smallest x can be is 1050[/sup]1/3[/sup]/3.In summary, the function y = 27x2 + 2100/x has one critical point for positive x, which occurs when x = (1050/27)1/3. This critical point is a local minimum for the function.
  • #1
recoil33
28
0
I have a function which is:

y = 27x2 + 2100/x
dy/dx = 54x - 2100/x2

Critical points are for what x values, is y undefined or equal to 0?

Therefore, in this case i can only see the value of 0, which would cause the function to be undefined. Due to x2 being on the denominator.

EDIT:

0 = 54x - 2100/x2
0 = 54x3 - 2100
((-2100)/(54))(1/3) = x

x = - 3.38
Although I'm looking for the amount of positive values of x, which y = 0.
So therefore, 1?

Question: "How many critical numbers does y have, for positive x?"
Solved, 1.

Which solved my next question, it's a local minimum.
______________________________________________________________________________

Give the exact value of the x that minimises y for positive x.
Could someone explain what i am looking for? I don't really understand.

I think.

P' = 54x - 2100/x2

Once x hits -3.38 it minises y?
Which is in decimal, but i could convert to a whole number?


Thank you.
 
Last edited:
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  • #2
hi recoil33! :smile:
recoil33 said:
Give the exact value of the x that minimises y for positive x.
Could someone explain what i am looking for? I don't really understand.

they're asking for the value of x that you already found
Once x hits -3.38 it minises y?
Which is in decimal, but i could convert to a whole number?

i don't understand what they mean by "exact" :confused:

unless they mean to keep it as (2100/54)1/3, = (1050)1/3/3
 
  • #3
recoil33 said:
I have a function which is:

y = 27x2 + 2100/x
dy/dx = 54x - 2100/x2

Critical points are for what x values, is y undefined or equal to 0?

Therefore, in this case i can only see the value of 0, which would cause the function to be undefined. Due to x2 being on the denominator.

EDIT:

0 = 54x - 2100/x2
0 = 54x3 - 2100
((-2100)/(54))(1/3) = x
You've misplaced the sign here. It should be x= (+2100/54)1/3

x = - 3.38
Although I'm looking for the amount of positive values of x, which y = 0.
So therefore, 1?

Question: "How many critical numbers does y have, for positive x?"
Solved, 1.

Which solved my next question, it's a local minimum.
______________________________________________________________________________

Give the exact value of the x that minimises y for positive x.
Could someone explain what i am looking for? I don't really understand.

I think.

P' = 54x - 2100/x2

Once x hits -3.38 it minises y?
Which is in decimal, but i could convert to a whole number?


Thank you.
First, again, when you set y'= 0, 0= 54x- 2100/x2 and add 2100/x2 to both sides it becomes 2100/x2= 54x or x3= +2100/54 so your sign was wrong- this value of x is positive. Of course, you can reduce that fraction slightly: 2100/54= 1050/27 so the exact value of x is
x= (1050/27)1/3= 1050[/sup]1/3[/sup]/3 as tiny-tim suggested.
 
Last edited by a moderator:

Related to What Is the Exact Value of x That Minimizes y for Positive x?

1. What is the Critical Points problem?

The Critical Points problem is a mathematical concept that involves finding the points on a function where the derivative is equal to zero. These points are known as critical points and are important in determining the behavior of a function.

2. Why is the Critical Points problem important?

The Critical Points problem is important because it helps us understand the behavior of a function and identify important points such as maximum and minimum values. This information is useful in various fields such as physics, economics, and engineering.

3. How do you find the Critical Points of a function?

To find the Critical Points of a function, you need to take the derivative of the function and set it equal to zero. Then, solve for the variable to find the critical points. These points can be further classified as local maxima, local minima, or saddle points based on the behavior of the function at that point.

4. What is the difference between a critical point and an inflection point?

A critical point is a point on a function where the derivative is equal to zero, while an inflection point is a point where the concavity of the function changes. In other words, at an inflection point, the slope of the tangent line changes from increasing to decreasing or vice versa. Critical points can help us identify inflection points, but not all critical points are inflection points.

5. How does the Critical Points problem relate to optimization?

The Critical Points problem is closely related to optimization because critical points can help us identify the maximum or minimum values of a function. In optimization problems, we often want to find the maximum or minimum value of a function, and critical points can help us do that by providing information about the behavior of the function at those points.

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