- #1
azure kitsune
- 65
- 0
Homework Statement
A Carnot air conditioner takes energy from the thermal energy of a room at 70 degrees F and transfers it to the outdoors, which is at 96 degrees F. For each joule of electric energy required to operate the air conditioner, how many joules are removed from the room?
Homework Equations
[tex]\frac{Q_C}{Q_H} = \frac{T_C}{T_H}[/tex]
The Attempt at a Solution
I substituted W + QC for QH. Then I plugged in
W = 1,
TC = (70-32) * 4/5+273,
TH = (96-32) * 4/5+273
and solved for QC.
I get QC = 20.3 J, but the answer in the back is rounded 21 J. When I read the problem, I thought the question was asking for QC. Should the 1 J or work be included in the amount of joules being removed from the room?