- #1
japplepie
- 93
- 0
d(x^^n)/dx = ?
moriheru said:What is (x^^n)?
Im only looking for the formula for integer values of x, will that make it simpler?Mentallic said:It's tetration which represents a double up arrow in Knuth's up arrow notation. Basically a power tower of x's n high:
[tex]x^{x^{.^{.^{.^x}}}}[/tex]
And I don't see any simple solution to this problem.
Sorry, what I meant was positive integers.HallsofIvy said:That function is not even defined for integer values of x.
It would be better if you type in latex.japplepie said:ok I got it
d(x ^^ n) / dx = x ^^ n * d(x ^^ ( n -1) * ln x ) / dx
Follow up question:
lim i→ ∞ { di(x ^^ n) / dxi } converge?
The derivative of a sexp() is a mathematical concept used in calculus to represent the rate of change of a function with respect to its independent variable.
The derivative of a sexp() can be calculated using the rules of differentiation, which involve taking the limit of the change in the function over the change in the independent variable as the change approaches 0.
The derivative of a sexp() has many practical applications in science and engineering, as it allows us to analyze the behavior of functions and make predictions about their future values.
Yes, the derivative of a sexp() can be negative, as it represents the slope of the function at a specific point. A negative value indicates a decreasing function, while a positive value indicates an increasing function.
Yes, the derivative of a sexp() is equal to the slope of the tangent line at a specific point on the function. This is because the tangent line represents the instantaneous rate of change of the function at that point, which is what the derivative measures.