What Is the Correct Slit Width for X-Ray Diffraction with a 10A Wavelength?

[Quelsita]

Problem:
Diffraction of X rays has been observed when a beam strikes an extremely fine slit. What must be the width if the slit if X rays of wavelength 10A are to display a diffraction pattern with a central beam of angular width 0.1?

I used Bragg's equation to obtain:
d=n(lambda)/2sin(theta)
d=1*10A/2sin(0.1)=2864.8A= 246.48nm?

Is this correct?

 

[alphysicist]

Hi Quelsita,

Problem:
Diffraction of X rays has been observed when a beam strikes an extremely fine slit. What must be the width if the slit if X rays of wavelength 10A are to display a diffraction pattern with a central beam of angular width 0.1?

I used Bragg's equation to obtain:
d=n(lambda)/2sin(theta)
d=1*10A/2sin(0.1)=2864.8A= 246.48nm?

Is this correct?

I don't believe you are using the correct equation here. Bragg's law describes diffraction by a crystal; here the process is single slit diffraction. What equation would describe that?

 

[Quelsita]

Could you use the grating equation d[sin(theta_m)+sin(theta_i)]=m(lambda)?
But what is theta_max?

 

[alphysicist]

Could you use the grating equation d[sin(theta_m)+sin(theta_i)]=m(lambda)?
But what is theta_max?

I think you should use the single slit diffraction equation. The equation for the minima is

[tex]
a\ \sin\theta =m\lambda
[/tex]

I would think that your book has at least a section on single slit diffraction, so it can tell you how to apply this to your problem. What do you get?