What Is the Capacitance Between Two Long Parallel Cylindrical Wires?

In summary, to find the capacitance of two long cylindrical conducting wires with a surface charge density that is uniformly distributed, we can use Gauss's law to find the electric potential between the wires. The limits of the integral can be found by choosing a reference point and integrating along the length of one of the wires. While Coulomb's law can also be used, it may be more complicated to consider the contributions of all the point charges on each wire.
  • #1
eman2009
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Homework Statement



tow long cylindrical conducting wire ,each of radius a and length l parallel and separated by d , and between the centers of the wires , d>>a ,and the surface charge densities is uniformly,then the total electris potential is the sum of each wire . the effect between them is neglected .

Homework Equations


show the capacitance of the wire is c=pi (l) epsolen /In(d/a)

The Attempt at a Solution


I tryed to separate the electric potential for each and use gauss's law
first for Q+
v=-INT E.da
=-Q/2piepsolin l INT ds/s ,s=a
but how the limit of the INT will be
and then find the other v for the other wire with Q-
I got for c=Q/v =2 pi epsolin l /In (a+/a-)

or may be use the coulomb's law insted
 
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  • #2
of gauss's law



Thank you for your post. I am a scientist and I would like to help you with your problem. From your post, I understand that you are trying to find the capacitance of two long cylindrical conducting wires with a surface charge density that is uniformly distributed. The wires are parallel and separated by a distance much larger than their radii. You have correctly identified that the total electric potential is the sum of the individual potentials of each wire. However, you are unsure about how to find the limits of the integral when using Gauss's law and you are also wondering if Coulomb's law can be used instead.

To find the limits of the integral, we need to consider the geometry of the system. Since the wires are parallel and separated by a distance much larger than their radii, we can assume that the electric field between the two wires is uniform. This means that the electric field lines are parallel and the electric field strength is the same at any point between the wires. Therefore, we can choose any point on one of the wires as our reference point and integrate along the length of the wire. The limits of the integral will be from 0 to l, where l is the length of the wire.

Now, let's consider Coulomb's law. This law states that the electric potential at a point due to a point charge is directly proportional to the magnitude of the charge and inversely proportional to the distance from the point charge. In our system, we have two wires with surface charge densities that are uniformly distributed. We can treat each wire as a collection of point charges and use Coulomb's law to find the potential at a point between the two wires. However, this approach may be more complicated than using Gauss's law since we would need to consider the contributions of all the point charges on each wire.

In conclusion, I would recommend using Gauss's law to find the electric potential between the two wires. Remember to choose a reference point and integrate along the length of one of the wires to find the limits of the integral. I hope this helps with your problem. Good luck!
 

Related to What Is the Capacitance Between Two Long Parallel Cylindrical Wires?

1. What is a cylindrical conducting material?

A cylindrical conducting material refers to a material that allows electricity to flow through it easily. This material has high electrical conductivity and low resistance, making it an efficient conductor of electricity.

2. How does the shape of a cylindrical conductor affect its conductivity?

The shape of a cylindrical conductor, specifically its length and cross-sectional area, can affect its conductivity. A longer conductor will have higher resistance, while a larger cross-sectional area will have lower resistance. This means that a shorter and thicker cylindrical conductor will have higher conductivity compared to a longer and thinner one.

3. What is the difference between a hollow and solid cylindrical conductor?

A hollow cylindrical conductor has an empty space inside, while a solid cylindrical conductor is completely filled with conducting material. The presence of an empty space in a hollow cylindrical conductor can affect its conductivity as it reduces the amount of conducting material available.

4. Are there any applications of cylindrical conductors?

Cylindrical conductors are commonly used in electrical wiring, as they provide a low-resistance pathway for electricity to flow. They are also used in the construction of motors, generators, and other electrical devices. Cylindrical conductors are also used in the production of magnets and electromagnets.

5. How can the conductivity of a cylindrical conductor be increased?

The conductivity of a cylindrical conductor can be increased by using a material with higher electrical conductivity, such as copper or silver. Additionally, reducing the length of the conductor and increasing its cross-sectional area can also improve conductivity. The temperature of the conductor can also affect its conductivity, as higher temperatures can increase resistance and decrease conductivity.

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