What Happens to the Fundamental Frequency When Modifying a Drinking Straw?

In summary, the fundamental frequency of a standing wave in a fairly large drinking straw is affected by certain actions. Covering the bottom of the straw with a fingertip while blowing decreases the frequency to half of the original. Cutting the straw in half decreases the frequency to 2/3 of the original. Cutting a third of the straw off increases the frequency to 3/2 of the original. Gluing an extension of half the length of the original straw increases the frequency to twice the original. In a closed pipe, the wavelength of the standing wave is 2 times the length of the pipe, while in an open pipe, it is 4 times the length of the pipe. The distance between a node and an anti-node depends on
  • #1
sonutulsiani
138
0

Homework Statement



If you blow air over the top of a fairly large drinking straw you can hear a fundamental frequency due to a standing wave being set up in the straw. Match the following actions with their consequent results:

1. While blowing, you cover the bottom of the straw with your fingertip.
2. While blowing you cut the straw in half with a pair of scissors.
3. While blowing you cut a third of the straw off with a pair of scissors.
4. While blowing you glue an extension of half the length of the original straw to the original straw.


A. The fundamental frequency increases. It is now 3/2 the original fundamental frequency.
B. The fundamental frequency decreases. It is now half of the original fundamental frequency.
C. The fundamental frequency increases. It is now twice the original fundamental frequency.
D. The fundamental frequency decreases. It is now 2/3 of the original fundamental frequency.


Homework Equations





The Attempt at a Solution



I just got 2-c. I don't know about the rest, please help.
 
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  • #2
In open pipe of length L, wave length of the standing wave is equal to 2L. In the closed pipe of the same length λ = 4L.
 
  • #3
So according to that 1b, 2c, 3a and 4d? Right?
 
  • #4
By the way my textbook says, closed it's λ = 2L and open it's λ = 4L
 
  • #5
Check this out http://ebooks.bfwpub.com/physse6e/figures/16_12_big.jpg and http://ebooks.bfwpub.com/physse6e/figures/16_18_big.jpg
 
Last edited by a moderator:
  • #6
sonutulsiani said:
By the way my textbook says, closed it's λ = 2L and open it's λ = 4L
Your answer in the above post is correct.
In the closed pipe open end is anti node and closed end is node. What is the distance between node and anti node?
 
  • #7
That depends on whether it is 1st or 2nd or 3rd.. harmonic right?
 
  • #8
But 1b, 2c, 3a and 4d correct?
 

Related to What Happens to the Fundamental Frequency When Modifying a Drinking Straw?

What is "Match the Frequencies"?

"Match the Frequencies" is a scientific method used to identify and compare the frequencies of different signals or waves, such as sound, light, or radio waves, in order to determine if they are the same or similar.

How does "Match the Frequencies" work?

The process of "Match the Frequencies" involves using a device, such as a spectrum analyzer, to measure the frequencies of two different signals and then comparing them to see if they match or are similar. This can help scientists identify patterns or relationships between different signals.

What are the applications of "Match the Frequencies"?

"Match the Frequencies" has various applications in fields such as physics, astronomy, and engineering. It can be used to study the properties of different signals, identify unknown signals, and even detect hidden or hidden patterns in data.

What are the advantages of using "Match the Frequencies"?

One major advantage of "Match the Frequencies" is that it allows scientists to accurately compare and analyze signals without being affected by external factors, such as distance or interference. It also provides a more objective and precise method of measurement compared to other techniques.

Are there any limitations to "Match the Frequencies"?

One limitation of "Match the Frequencies" is that it can only compare signals with similar frequencies, so it may not be applicable in all situations. Additionally, it may not be able to detect signals with very low or high frequencies, as some devices have limited frequency ranges.

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