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Interception
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Can you post those equations? It is hard to spot specific problems based on that description.I was able to isolate the mass the just fine, it's when I try to find radius and velocity that complicate it. When I solve it for the second for radius however, I have r on both sides of the equation. For velocity, I just get the quantity 2∏r/T on one side with the rest on the other. It just looks messy to me. I was thinking for the radius issue, I could get rid of the r on the other side of the equation by making it 1/2(diameter)? I'm lost here. I'd appreciate some help.
Centripetal force is a force that acts towards the center of a circular motion, keeping an object moving in a curved path. It is also known as the "center seeking" force.
The first equation for Centripetal Force is F = m x v^2 / r, where F is the centripetal force, m is the mass of the object, v is the velocity, and r is the radius of the circular motion.
The second equation for Centripetal Force is F = m x ω^2 x r, where F is the centripetal force, m is the mass of the object, ω is the angular velocity, and r is the radius of the circular motion.
Centripetal force can be calculated using either of the two equations: F = m x v^2 / r or F = m x ω^2 x r. These equations take into account the mass, velocity, angular velocity, and radius of the circular motion.
Centripetal force and centripetal acceleration are directly proportional. This means that as centripetal force increases, so does centripetal acceleration, and vice versa. The relationship between the two can be expressed as F = m x a, where F is the centripetal force and a is the centripetal acceleration.