Wave Pulse on a String: Free End at Point O

In summary: Good job!In summary, when a wave pulse on a string is reflected at a fixed end, the reflection causes the wave to flip upside down. However, when the end of the string is free to move, the wave does not flip. This difference in reflection results in a different shape of the wave when combining the incoming and outgoing halves. The amplitude of the wave remains the same in both cases, but the direction of movement and shape of the wave are different. If the end of the string is fixed, the wave will flip and become a straight line when the incoming and outgoing halves are combined. However, if the end is free to move, the wave will not flip and the shape will remain the same.
  • #1
varunika
19
0
a wave pulse on a string has the dimension shown in figure (see attachment) the wave speed is v=1 cm/s. point o is a free end, the shape of wave at time t=3s is?
someone please explain why would the answer to this question differernt if the point O was a fixed end?
how does it make a difference if the string is fixed at both the ends or at a single only??
 

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  • #2
varunika said:
a wave pulse on a string has the dimension shown in figure (see attachment) the wave speed is v=1 cm/s. point o is a free end, the shape of wave at time t=3s is?
someone please explain why would the answer to this question differernt if the point O was a fixed end?
how does it make a difference if the string is fixed at both the ends or at a single only??

The reflection you get from a fixed end of the string is different from the reflection you get if the end of the string is open (like if it is a frictionless ring on a vertical rod, so it is free to move up and down without resistance.

Can you tell us what is different about the two reflections (first when the string end is fixed, and second when it is free to move)?
 
  • #3
berkeman said:
The reflection you get from a fixed end of the string is different from the reflection you get if the end of the string is open (like if it is a frictionless ring on a vertical rod, so it is free to move up and down without resistance.

Can you tell us what is different about the two reflections (first when the string end is fixed, and second when it is free to move)?

i am sorry sir... but i didnt get your point.
please explain..
 
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  • #4
when the end is fixed the wave flips upside down upon reflection. That doesn't happen when the end es free to move in which case the wave doesn't flip. In that question you're asked to draw the shape of the string halfway through reflection which means half of the wave is still coming in while the other half has already reflected and is moving back out. depending on the kind of reflection (flip or no-flip) you will obviously get a different shape when you combine the incoming half with the outgoing half.
 
  • #5
dauto said:
when the end is fixed the wave flips upside down upon reflection. That doesn't happen when the end es free to move in which case the wave doesn't flip. In that question you're asked to draw the shape of the string halfway through reflection which means half of the wave is still coming in while the other half has already reflected and is moving back out. depending on the kind of reflection (flip or no-flip) you will obviously get a different shape when you combine the incoming half with the outgoing half.

you mean the final amplitude after reflection will become 2cm?
 
  • #6
yes, you figured it out
 
  • #7
What do you think would happen if the end was fixed?
 
  • #8
i assume the amplitude would remain same...and the wave would flip to the opposite direction.. am i right?
 
  • #9
varunika said:
i assume the amplitude would remain same...and the wave would flip to the opposite direction.. am i right?

Yes, the wave flips. What happens when you add half a wave going in with the other half coming out considering that the reflected part has flipped upside-down?
 
  • #10
the wave would become stationary?
 
  • #11
varunika said:
the wave would become stationary?

Stationary would mean the string stops moving. That doesn't happen since the wave will continue its motion. We're talking about the shape of the wave, not its movement.
 
  • #12
would it become a straight line?
 
  • #13
varunika said:
would it become a straight line?

That's right. You're better at physics than you seem to believe.
 
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Related to Wave Pulse on a String: Free End at Point O

1. What is a wave pulse on a string with a free end at point O?

A wave pulse on a string with a free end at point O is a phenomenon that occurs when a disturbance or energy is introduced to a string with one end fixed (point O) and the other end free. This results in a single wave traveling through the string.

2. How does a wave pulse on a string with a free end at point O differ from other types of waves?

A wave pulse on a string with a free end at point O differs from other types of waves in that it is a single, isolated disturbance that travels through the string, rather than a continuous oscillation.

3. What factors affect the speed of a wave pulse on a string with a free end at point O?

The speed of a wave pulse on a string with a free end at point O is affected by the tension in the string, the mass of the string, and the length of the string. Generally, a higher tension, lower mass, and shorter length will result in a faster wave pulse.

4. Can a wave pulse on a string with a free end at point O reflect?

Yes, a wave pulse on a string with a free end at point O can reflect when it reaches the free end. This reflection can be seen as the wave pulse traveling back in the opposite direction through the string.

5. How is the amplitude of a wave pulse on a string with a free end at point O affected by distance?

The amplitude of a wave pulse on a string with a free end at point O decreases as the wave travels along the string away from the fixed end. This is due to energy being transferred to the string and the wave spreading out over a larger area.

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