Wave Equation Spherical Perturbations

In summary, the conversation discusses the solution to the tridimensional wave equation, u(r,t)=\frac{f(r-vt)}{r}, and shows that it corresponds to a spherical perturbation centered at the origin and going away from it with velocity v. The conversation also assumes that f is twice differentiable and uses the wave equation to find the expression for the Laplacian, which is then used to show that the wave equation is satisfied. However, there may be some errors in the setup of the problem or in the calculations.
  • #1
fluidistic
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Homework Statement


Show that [tex]u(r,t)=\frac{f(r-vt)}{r}[/tex] is a solution to the tridimensional wave equation. Show that it corresponds to a spherical perturbation centered at the origin and going away from it with velocity v. Assume that f is twice differentiable.

Homework Equations



The wave equation: [tex]\frac{\partial ^2 u }{\partial t ^2}- c^2 \triangle u =0[/tex].

The Attempt at a Solution


I just used the wave equation and found out that [tex]\frac{\partial ^2 u}{\partial t^2} = v^2 u''[/tex].
While [tex]\triangle u =\frac{1}{r} \left [ u''+ \frac{u}{r^2} - \frac{2u'}{r} \right ][/tex].
So the wave equation is satisfied if [tex]u'' \left ( v^2-\frac{c^2}{r} \right ) + \frac{2 c^2 u'}{r^2} - \frac{u c^2}{r^3}=0[/tex].
It's likely wrong so either I set up badly the problem, either I set it up OK but made some errors.
 
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  • #2
fluidistic said:
While [tex]\triangle u =\frac{1}{r} \left [ u''+ \frac{u}{r^2} - \frac{2u'}{r} \right ][/tex].
I think that's your problem. Where did you get this expression for the Laplacian?
 

Related to Wave Equation Spherical Perturbations

1. What is the wave equation for spherical perturbations?

The wave equation for spherical perturbations is a partial differential equation that describes the propagation of waves in a three-dimensional spherical coordinate system. It is commonly used in fields such as electromagnetics, acoustics, and fluid dynamics.

2. How is the wave equation for spherical perturbations derived?

The wave equation for spherical perturbations is derived from the general wave equation by taking into account the spherical symmetry of the system. This involves converting the Laplacian operator into spherical coordinates and applying the appropriate boundary conditions.

3. What are some real-world applications of the wave equation for spherical perturbations?

The wave equation for spherical perturbations has a wide range of applications in various fields. For example, it is used to model the propagation of sound waves in spherical resonators, the behavior of electromagnetic waves in spherical antennas, and the movement of fluids in spherical containers.

4. How does the wave equation for spherical perturbations differ from the wave equation for Cartesian coordinates?

The wave equation for spherical perturbations differs from the wave equation for Cartesian coordinates in that it takes into account the spherical symmetry of the system. This means that the spherical wave equation has additional terms that account for the radial component of the wave and the spherical coordinate system.

5. Can the wave equation for spherical perturbations be solved analytically?

In most cases, the wave equation for spherical perturbations cannot be solved analytically and requires numerical methods for solution. However, there are some special cases where analytical solutions exist, such as for simple harmonic oscillators and spherical wave sources.

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