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mathman44
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Homework Statement
I can't seem to get a start on this. Could anyone provide a hint or something to get me started? Thanks...
mathman44 said:Anybody? I tried setting the "right" impedance equal to 1/9th of the "left" impedance to reform the voltage divider but this is a huge mess.
A voltage divider is an electrical circuit that is used to divide a larger voltage into a smaller voltage. It is commonly used in electronic circuits to provide a specific voltage to a component.
A voltage divider is made up of two or more resistors in series. The voltage across each resistor is proportional to its resistance, so the total voltage is divided between the resistors. This creates a smaller voltage at the output of the divider.
A capacitor is not necessary for a voltage divider to function, but it can be used to help stabilize the output voltage and filter out any unwanted noise or fluctuations. It can also be used to adjust the output voltage by changing its capacitance.
Without a capacitor, the output voltage of the divider may be less stable and more susceptible to noise or fluctuations. It may also be difficult to adjust the output voltage without the presence of a capacitor.
To calculate the output voltage of a voltage divider without a capacitor, you will need to know the values of the resistors in the circuit and use Ohm's Law (V=IR) to determine the voltage drop across each resistor. The total output voltage will be the sum of the voltage drops across each resistor.