- #1
robot1000
- 5
- 0
The question I'm trying to solve is:
y" - 6y' + 9y = [itex]\frac{exp(3x)}{(1+x)}[/itex]
I formulated the Gen solution which are:
y1(x) = exp(3x) and y2(x) = xexp(3x)
I've then calculated the wronskian to get: exp(6x)
I then went onto to use the variation of parameters formula, which is where I got a bit stuck
I ended up with
-exp(3x)*(x - ln(x+1) + xexp(3x)*ln(1+x)
The problem is, it just doesn't look right.
I would appreciate some guidance with this problem
y" - 6y' + 9y = [itex]\frac{exp(3x)}{(1+x)}[/itex]
I formulated the Gen solution which are:
y1(x) = exp(3x) and y2(x) = xexp(3x)
I've then calculated the wronskian to get: exp(6x)
I then went onto to use the variation of parameters formula, which is where I got a bit stuck
I ended up with
-exp(3x)*(x - ln(x+1) + xexp(3x)*ln(1+x)
The problem is, it just doesn't look right.
I would appreciate some guidance with this problem