- #1
Tonyant
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hi guys, I'm new to this beautiful forum and i signed up to ask a question that drives me nuts for weeks. I am german so my english sucks but, i learned about this experiment with the quantum eraser. basically the experiment goes like this. you shoot photons through a double slit and behind the slits you have a crystal that splits them in 2 identical twins. one twin goes at a wall where the pattern will be seen the other goes to a detector. of course when one twin photon is detected the other one looses its wavefunction. so far so quantum weird. now you put 2 more detectors behind the 2 first ones and the photon has a 50% chance to hit those instead of the 2 first ones. the second detectors are build up so that you can't say what slit the photon took. so whenever a photon hits the first detector it's twin has no wave function whenever the photon hits the second detector the photon does have a wavefunction and an interference pattern emerges. my question is how do we know which photon at the "wall" is the twin of which photon in the detectors? and even more important why was there no experiment with only the 2. pair of detectors?`everytime i research it the experiment is build that half the photons are detected and half not. than people say the photons that got detected formed a clunk pattern while the photons that went to the second detector formed an interference pattern. but how can you tell which photon belonged to which twin? :D :D
i'm confused and i can't find it on google because i only find articles about how weird the whole thing is.
well thanks for reading it's probably a stupid question i know :D
i'm confused and i can't find it on google because i only find articles about how weird the whole thing is.
well thanks for reading it's probably a stupid question i know :D