- #1
SgtSniper90
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Uniform Circular motion problem!
A 235 m tall tower is built on the equator. Due to the rotation of the earth, how much faster does a point at the top of the tower move than a point at the bottom (in m/s)?
v=w*r (w is omega)
So it didnt give me the radius of the Earth but the previous problem said it was 6400 km so i used that and converted 365 days to seconds and got 31536000. Next i tried to find the velocity of the Earth in m/s so 6400km= 6400000 m. 6400000m/31536000s. i get 0.2029426687. i do the same thing but at 235 to the radius and i get 0.2029426687. I next found the difference and get 7.45*10-6. Its not right i don't know what I am doing wrong...
Homework Statement
A 235 m tall tower is built on the equator. Due to the rotation of the earth, how much faster does a point at the top of the tower move than a point at the bottom (in m/s)?
Homework Equations
v=w*r (w is omega)
The Attempt at a Solution
So it didnt give me the radius of the Earth but the previous problem said it was 6400 km so i used that and converted 365 days to seconds and got 31536000. Next i tried to find the velocity of the Earth in m/s so 6400km= 6400000 m. 6400000m/31536000s. i get 0.2029426687. i do the same thing but at 235 to the radius and i get 0.2029426687. I next found the difference and get 7.45*10-6. Its not right i don't know what I am doing wrong...