Understanding Voltage in EM Circuits: A Student's Query

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In summary, the concept of voltage is defined differently in different contexts. In the electrostatic context, it is defined as the line integral of electric field over a path. However, in circuits with inductors and time-varying current, the line integral of electric field is path-dependent due to the non-zero curl of electric field. To simplify the calculation, the concept of quasi-static approximation is used, where the time-varying electric field is approximated as solely due to a time-varying scalar potential. In this case, voltage is defined as the line integral of the conservative electric field over a path. However, there are still some debates and confusion about the concept of voltage and its definition, particularly in the case
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pmr
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I'm currently taking an EM course. We're doing AC circuits, but I'm having a hard time understanding how voltage is defined.

In the electrostatic context I understand how the voltage is defined as the line integral of E over a path, and I get how that line integral has nice path-independent properties because E has no curl. But then our course introduces magnetism, and circuits. The sort of circuits we're looking at have inductors, or lots of self-inductance, so even magneto-statics goes out the window.

When I ask about how voltage is defined in this more complicated context I get lots of answers like "voltage is still just the integral of E * dl", but I'm not happy with that because it's path-dependent, and therefore meaningless unless a convention is chosen for taking the path (which I've never seen done), or unless an argument is given for why that detail isn't important (which I've also never seen done).

I also sometimes get answers like "voltage is just the difference in potential energy divided by charge," but I'm also not happy with that because people giving this answer uniformly fail to answer the follow-up question of "what is potential energy?" You can't define electric potential energy in usual way, for the reasons I just explained in the last paragraph. And anyway there are some choices of gauge for which the [itex]\phi[/itex] in [itex]\vec E = -\nabla\phi - d{\vec A}/dt[/itex] is declared by fiat to be [itex]\phi=0[/itex] everywhere and at all times (which has interesting consequences for how [itex]\vec A[/itex] has to be defined, but nonetheless renders the concept of the scalar potential null and void).

Lastly, I get a lot of people saying that I'm overcomplicating things. But all I'm asking is for some definition of this pervasively used concept of "voltage" that doesn't have big gaping holes in it. I don't think that's too much to ask for, and I think it's worth nitpicking about. If there are assumptions or approximations going on that render my nitpicking extraneous, then I want to know exactly what those assumptions or approximations are.

Also, to the admins: I wasn't sure where to post this question. If I'm in the wrong section then feel free to move me.
 
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pmr said:
When I ask about how voltage is defined in this more complicated context I get lots of answers like "voltage is still just the integral of E * dl", but I'm not happy with that because it's path-dependent, and therefore meaningless unless a convention is chosen for taking the path (which I've never seen done), or unless an argument is given for why that detail isn't important (which I've also never seen done).

No, it's not path-dependent. Say you have a coil with some electric field induced in the turns. You may, during integration of the total voltage-difference over the coil, choose a path through the turns and get a result, or you may choose a path that jumps from one turn, through an airgap, to another turn (missing one or more turns). You will get the same result because in the airgap there will be an electric field (induced by the voltage-difference between one turn to the other), and when you integrate through this airgap, you will exactly get a voltage-difference that matches the voltage-difference integrated through the missing turns. So you may choose the path as you like, making loops, jumps, whatever: You will get the same result.

( I don't know if I have understood your confusion correctly here? )
 
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  • #3
You are right that in AC circuits and generally circuits with time varying current the line integral of E depends on the path because CurlE is not zero, however you do the so called "quasi static" approximation that CurlE=0 , which essentially means that the time varying of E is solely due to a time varying scalar potential [itex]\phi[/itex].

It should be clear how this approximation works in the case of a capacitor (where the time varying E between its plates is mainly due to the time varying charge accumulation in its plates which creates a time varying scalar potential, that is for frequencies of no more than a few Ghz).

In the case of inductor, the time varying vector potential A and the associated non conservative electric field [itex]E_{\vec{A}}=-\frac{d\vec{A}}{dt}[/itex] initiate the process of creating surface charges in the surface of the wire that the inductor is made, which surface charge result in a conservative electric field [itex]E_{\phi}=-\nabla\phi[/itex] such that the total electric field [itex]E_{\phi}+E_{\vec{A}}\approx 0[/itex] is almost zero in the region inside the wire of the inductor. So you can take as E just the conservative constituent [itex]E_{\phi}[/itex] and define as [itex]V=\int E_{\phi}dr=-\int E_{\vec{A}}dr[/itex].
 
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Related to Understanding Voltage in EM Circuits: A Student's Query

1. What is voltage and why is it important in EM circuits?

Voltage, also known as electromotive force, is the potential difference between two points in an electrical circuit. It is a measure of the energy required to move a unit of electric charge between those two points. In EM circuits, voltage is important because it is the driving force that causes electric charges to move through a circuit and power electronic devices.

2. How is voltage calculated in an EM circuit?

Voltage can be calculated using Ohm's Law, which states that voltage is equal to the current flowing through a circuit multiplied by the resistance of the circuit. This can be expressed mathematically as V = IR, where V is voltage, I is current, and R is resistance. Voltage can also be calculated using Kirchhoff's Voltage Law, which states that the sum of all voltage drops in a closed loop circuit must equal the sum of all voltage rises.

3. What factors affect the voltage in an EM circuit?

The voltage in an EM circuit can be affected by a number of factors, including the type of power source being used, the resistance of the circuit, and the number and arrangement of components in the circuit. Changes in these factors can result in changes in the voltage, which can impact the overall performance of the circuit and the devices connected to it.

4. How does voltage impact the behavior of components in an EM circuit?

The voltage in an EM circuit can have a significant impact on the behavior of components such as resistors, capacitors, and inductors. These components have different properties that determine how they respond to changes in voltage. For example, resistors resist the flow of electric current, while capacitors store and release electric charge, and inductors resist changes in current. Understanding voltage is crucial in designing and troubleshooting EM circuits to ensure the proper functioning of these components.

5. How can I measure voltage in an EM circuit?

There are several ways to measure voltage in an EM circuit, including using a voltmeter, an oscilloscope, or a multimeter. These tools can provide accurate readings of voltage at specific points in the circuit, allowing you to troubleshoot and adjust the circuit as needed. It is important to use the appropriate tools and follow safety precautions when measuring voltage in an EM circuit.

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