- #1
prasannapakkiam
take the function: y = x^x
if x<0; it is not defined. However:
take this example:
x=-3
therefore: y=(-3)^(-3)
=1 / ( (-3)^3 )
=-27
HOWEVER: y == e^(xln(x))
ln(x) has a domain: {x>0, x e R}
Thus in that respect when x=-3, it is undefined.
WHY?
if x<0; it is not defined. However:
take this example:
x=-3
therefore: y=(-3)^(-3)
=1 / ( (-3)^3 )
=-27
HOWEVER: y == e^(xln(x))
ln(x) has a domain: {x>0, x e R}
Thus in that respect when x=-3, it is undefined.
WHY?