- #1
axe34
- 38
- 0
Hi,
I'm trying to prove that the integral of x^3 (x cubed) between the limits of a (lower limit) and b (upper limit) is:
(b^4)/4 - (a^4)/4
I'm using the traditional method of dividing the area into n rectangles (where n tends to infinity). Hence the width of 1 rectangle is (b-a)/n
The x coordinate (left side of each thin rectangle) of any rectangle is: a + (k-1) * ((b-a)/n)
I can prove other integrations using this 'traditional' approach but cannot get the correct answer here.
Does anyone have a link to the proof or can provide it?
Thanks. This is driving me mad.
I'm trying to prove that the integral of x^3 (x cubed) between the limits of a (lower limit) and b (upper limit) is:
(b^4)/4 - (a^4)/4
I'm using the traditional method of dividing the area into n rectangles (where n tends to infinity). Hence the width of 1 rectangle is (b-a)/n
The x coordinate (left side of each thin rectangle) of any rectangle is: a + (k-1) * ((b-a)/n)
I can prove other integrations using this 'traditional' approach but cannot get the correct answer here.
Does anyone have a link to the proof or can provide it?
Thanks. This is driving me mad.