- #1
Punit D
- 2
- 0
I'm wondering if anyone can answer this question for me.
Suppose we send a spaceship to the moon at 299,792,457 m/s (1m/s less than c). That's 99.9999997% of the speed of light. Plugging the numbers into the time dilation formula, we get that the 1.2822 seconds that it takes for the spaceship to reach the moon is equal to 15,698.4954 seconds on earth, or 3 hours and 24 mins roughly.
My question is, what exactly do we see here from Earth? Suppose an observer with a telescope is watching the spaceship take off and reach it's destination. We already know the spaceship will take about 1.28 seconds to reach the moon, yet the observer holds the telescope in his hand and watches the spaceship for 3 hours and 24 mins? I'm confused here.
Suppose we send a spaceship to the moon at 299,792,457 m/s (1m/s less than c). That's 99.9999997% of the speed of light. Plugging the numbers into the time dilation formula, we get that the 1.2822 seconds that it takes for the spaceship to reach the moon is equal to 15,698.4954 seconds on earth, or 3 hours and 24 mins roughly.
My question is, what exactly do we see here from Earth? Suppose an observer with a telescope is watching the spaceship take off and reach it's destination. We already know the spaceship will take about 1.28 seconds to reach the moon, yet the observer holds the telescope in his hand and watches the spaceship for 3 hours and 24 mins? I'm confused here.