- #1
Raresss
- 4
- 0
How can I calculate the thrust of an underpressure tank of air when the valve is released? If you can, please, explain in detail. Thank you!
More than the ambient pressureBystander said:"Underpressure?" Less than ambient?
Pressure "under" what? Do you mean when it's running out?Raresss said:More than the ambient pressure
I can see that now. In English, underpressure and "underweight" (compound words) have different meanings from when the two words are separated by a space; hence my confusion. If this were a German forum, things might be different. . .CWatters said:The OP just means the thrust produced by air escaping from a cylinder of compressed air.
Most people in my country understand "under" to mean "due to". As in "The bridge failed under the weight of traffic".
Raresss said:Can the mass flow rate and the velocity of the exhausted gas be calculated or those can only be measured in an experiment ?
sophiecentaur said:If this were a German forum, things might be different. . .
Your force is the normal force, and your pressure is the surface pressure. We can't use those in my problem. The thrust is based on other variables . Check out this link to find out more : https://en.wikipedia.org/wiki/Thrustmrspeedybob said:Would it not just be the pressure in the tank x the area of the orifice?
I.E. If the pressure is 1 Mpa (above ambient) and the orifice is 12mm then the thrust should be 1 Newton, right?
The thrust of an underpressure tank of air refers to the force generated by the pressurized air inside the tank. This force is typically measured in Newtons (N) and is responsible for propelling the tank and any attached objects in the opposite direction.
The thrust of an underpressure tank of air is calculated using the formula F = PA, where F is the force in Newtons, P is the pressure in pascals (Pa), and A is the cross-sectional area of the tank's opening in square meters (m^2).
The thrust of an underpressure tank of air is affected by several factors, including the pressure inside the tank, the cross-sectional area of the tank's opening, and the mass of the air being expelled. Additionally, the shape and design of the tank can also impact the thrust generated.
The thrust generated by an underpressure tank of air is typically lower than that of an overpressure tank. This is because the air inside an underpressure tank is being sucked out, while the air in an overpressure tank is being pushed out, resulting in a greater force.
The thrust generated by an underpressure tank of air is used in various practical applications, such as in pneumatic devices, rocket engines, and air-powered tools. It is also an important factor in the design and functioning of vacuum cleaners and air compressors.