- #1
morrobay
Gold Member
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Thermal Conductivity , k , for water is .1455 cal/sec/ meter * C ( converted watts to cal/sec)
Q/t = k* A delta T/ d
A= area M2
d = thickness of water/ice boundary layer
Suppose I want to calculate time for 100 grams of ice to melt ( 8000 calories absorbed
from surroundings by conduction.
I have delta T and initial surface area of ice/water interface .
Two questions : What would be the boundary layer thickness. d
And in the case that the surface area, A, is decreasing as the ice melts is it correct to
use just the initial surface area in the calculation ?
My reasoning on the area is that it would actually be : Integral A(initial) - A(final) and
A(final ) = 0
Q/t = k* A delta T/ d
A= area M2
d = thickness of water/ice boundary layer
Suppose I want to calculate time for 100 grams of ice to melt ( 8000 calories absorbed
from surroundings by conduction.
I have delta T and initial surface area of ice/water interface .
Two questions : What would be the boundary layer thickness. d
And in the case that the surface area, A, is decreasing as the ice melts is it correct to
use just the initial surface area in the calculation ?
My reasoning on the area is that it would actually be : Integral A(initial) - A(final) and
A(final ) = 0
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