The Proper Time in Lorentz Space: Is it Infinite for the Resting Twin?

In summary, when m=0, the Schwarzschild spacetime becomes Lorentz spacetime. In this scenario, the proper time taken by one twin (A) to travel around the massive body in Lorentz space while the other twin at rest can be calculated using the formula t=2πR/v, where t is the time measured by the "stay at home" twin and R is the radius of the circular path. This means that the proper time can be defined and is not infinite.
  • #1
Nilupa
18
0
We know, when m=0, the schwarzschild space time becomes lorentz space time. Then, the proper time taken by one twin (A) to travel around the massive body in lorentz space while the other twin at rest can not be defined or it will be infinite. Is that true?
 
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  • #2
If m = 0, there is no massive body. I'm not sure what scenario you are imagining.
 
  • #3
Nilupa said:
We know, when m=0, the schwarzschild space time becomes lorentz space time. Then, the proper time taken by one twin (A) to travel around the massive body in lorentz space while the other twin at rest can not be defined or it will be infinite. Is that true?

Do you mean "when r is very large, far enough away from the mass that spacetime is effectively flat"? Otherwise I can't make sense of the question.

If that's what you mean, the proper time for a twin traveling in a giant circle is perfectly well defined and it's not zero - it's whatever the traveler's wristwatch records on the trip. It can calculated by computing the integral of ds along the path (and remember that the path is a closed curve in three-dimensional space but not in four-dimensional spacetime).
 
  • #4
Then, in de sitter space, also m=0. But, we can have some possible values for the proper time.
 
  • #5
Nilupa said:
Then, in de sitter space, also m=0. But, we can have some possible values for the proper time.

I think you need to be more explicit about exactly what types of trajectories you are talking about in which spacetimes.
 
  • #6
Nugatory said:
Do you mean "when r is very large, far enough away from the mass that spacetime is effectively flat"? Otherwise I can't make sense of the question.

If that's what you mean, the proper time for a twin traveling in a giant circle is perfectly well defined and it's not zero - it's whatever the traveler's wristwatch records on the trip. It can calculated by computing the integral of ds along the path (and remember that the path is a closed curve in three-dimensional space but not in four-dimensional spacetime).

Yes, thanks, I can understand.
 
  • #7
Nilupa said:
We know, when m=0, the schwarzschild space time becomes lorentz space time. Then, the proper time taken by one twin (A) to travel around the massive body in lorentz space while the other twin at rest can not be defined or it will be infinite. Is that true?

No, it is not true, whhere did you get that? In the absence of any gravitational body (your [itex]m=0[/itex]), a circular path traversed by the "traveling twin" takes the amount of time [itex]\tau=\frac{2 \pi R}{v}\sqrt{1-(v/c)^2}[/itex]. The "stay at home" twin , measures on his clock the time [itex]t=\frac{2 \pi R}{v}[/itex]. Here [itex]R[/itex] is the radius of the circular path and [itex]v[/itex] is the speed of the "traveling" twin wrt the "stay at home" twin. The calculations are very simple.
 

Related to The Proper Time in Lorentz Space: Is it Infinite for the Resting Twin?

1. What is proper time in Lorentz Space?

Proper time in Lorentz Space refers to the time experienced by an object or observer in its own reference frame. It is a fundamental concept in special relativity and is used to measure the duration of events in space-time.

2. How is proper time different from coordinate time?

Coordinate time is the time measured by a distant observer in a different reference frame, while proper time is the time measured in the reference frame of the object or observer itself. This means that proper time takes into account the effects of time dilation and length contraction in special relativity.

3. What is the significance of proper time in physics?

Proper time is a crucial concept in the theory of special relativity, as it allows for the calculation of physical quantities such as velocity and acceleration in different reference frames. It also helps to reconcile the discrepancies between Newtonian mechanics and the observed behavior of objects at high speeds.

4. How is proper time calculated in Lorentz Space?

Proper time is calculated using the Lorentz transformation equations, which take into account the relative velocity between two reference frames. The proper time can be calculated by integrating the time component of the Lorentz transformation over a specified duration.

5. Can proper time be negative in Lorentz Space?

No, proper time is always positive in Lorentz Space. This is because time dilation, which is a factor in the calculation of proper time, only occurs when an object is moving at speeds close to the speed of light. At these speeds, the time dilation factor is always greater than 1, resulting in a positive proper time.

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