- #1
Omid
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Here is a problem, please let me know whether my answer is right or wrong.
Locate the position of a spaceship on the Earth-Moon center line such that the tug of each celestial body exerts on it would cancel and the craft would literally be weightless.
I found two equations:
A.
(Distance between the aircraft and the Earth) + (Distance between the aircraft and Moon) = (Distance between the Earth and Moon)
B.
(The gravitational force between the aircraft and Moon) = ( The gravitational force between the aircraft and the Earth)
After doing the Algebra:
The distance between the aircraft and the Earth = 350 * 10^6 meters
Distance between the aircraft and Moon = 34 * 10^6 meters
As I expected, the air craft is nearer to Moon. So the less distance will cancel by the more mass of the Earth. But there is a question. If my answer is right, I'll ask it.
Thanks
Locate the position of a spaceship on the Earth-Moon center line such that the tug of each celestial body exerts on it would cancel and the craft would literally be weightless.
I found two equations:
A.
(Distance between the aircraft and the Earth) + (Distance between the aircraft and Moon) = (Distance between the Earth and Moon)
B.
(The gravitational force between the aircraft and Moon) = ( The gravitational force between the aircraft and the Earth)
After doing the Algebra:
The distance between the aircraft and the Earth = 350 * 10^6 meters
Distance between the aircraft and Moon = 34 * 10^6 meters
As I expected, the air craft is nearer to Moon. So the less distance will cancel by the more mass of the Earth. But there is a question. If my answer is right, I'll ask it.
Thanks