Tangential Velocity, Frames, and the Speed of Light

In summary, the conversation discusses a mental experiment involving two approaching ships and an observer in a stationary craft. The observer has questions about the velocity of the ships and the frame of reference in which they are measured. There is also a discussion about the limitations and complications of using a rotating frame of reference.
  • #1
Nishmaster
3
0
Hello gurus,

I have a mental experiment that I'm wrangling with.

Assume for a moment that two craft (Ship A and Ship B) are approaching each other at a significant fraction of c. Let us also assume that I, the observer, am in a stationary craft a large distance away rotating with the plane given by the vector of the two approaching craft, keeping one of them (Ship A) stationary in the center of my field of vision.

I have two questions:

1. Since I have no way of measuring the velocity of Ship A in my frame, is it assumed to be zero?

2. What would I measure as the velocity of Ship B?

I'm no mathematician of this level, but by all means don't dumb it down for me, as I'm really trying to pick some of this up. :smile:
 
Physics news on Phys.org
  • #2
You haven't specified the scenario properly because

.. I, the observer, am in a stationary craft ..

has no meaning unless you say in which frame of reference you are stationary. Presumably you mean to take your own ship as the stationary frame ?

Also, I'm puzzled as to why you think you can't measure the velocity of the other ships.

If you can measure one, why not the other ?
 
  • #3
Nishmaster said:
1. Since I have no way of measuring the velocity of Ship A in my frame, is it assumed to be zero?

2. What would I measure as the velocity of Ship B?
In what coordinate system are you asking for the velocities of the ships? If you want a coordinate system where every part of your craft is at rest, this would be a rotating coordinate system, and thus a non-inertial one, and there isn't really a single coordinate system which is "the" rest frame of a non-inertial observer, you can construct a variety of different coordinate systems where any given non-inertial object is at rest. On the other hand, if you want the inertial frame where the center of your craft is at rest while the rest of it rotates around it, then your own rotation is irrelevant to calculating the velocities of the ships in this frame.
 
  • #4
Yes, the frame here I am referring to would be a rotating coordinate system, where every part of my craft is at rest.

I guess my more overarching question perhaps is this:

Ignore the fact that ships have mass for a second and assume Ship A and B are both traveling at 1c. My observer craft is at 1 light second from the collision point, and each ship is also 1 light second from the collision point. So now, I have an equilateral triangle between myself, the collision point, and Ship A, if that makes any sense.

I can find that at the start of this experiment I am 45 degrees from where I will be when the ships collide, thus my rotational velocity is roughly 14.32 rad/s. Since I am rotating with respect to Ship A, I would measure using Pythagoras that Ship A is 1.41 (sqrt(2)) light seconds away at the start, and 1 light second away at the end, and thus is moving toward me at .41 light seconds/s.

My question is: What would I measure as the speed of Ship B? Would it be greater than c?

Something I just realized is that I suppose my rotational velocity is not constant. It would have to be accelerating to keep Ship A stationary with respect to the x component of its vector.
 
  • #5
Nishmaster said:
Yes, the frame here I am referring to would be a rotating coordinate system, where every part of my craft is at rest.
Then, as Mintz114 said, you are not in an enertial frame of reference and the usual formulas for special relativity do not apply.

I guess my more overarching question perhaps is this:

Ignore the fact that ships have mass for a second and assume Ship A and B are both traveling at 1c. My observer craft is at 1 light second from the collision point, and each ship is also 1 light second from the collision point. So now, I have an equilateral triangle between myself, the collision point, and Ship A, if that makes any sense.

I can find that at the start of this experiment I am 45 degrees from where I will be when the ships collide
How do you do that? The angles in an equilateral triangle are 60 degrees, not 45 degrees.

, thus my rotational velocity is roughly 14.32 rad/s. Since I am rotating with respect to Ship A, I would measure using Pythagoras that Ship A is 1.41 (sqrt(2)) light seconds away at the start, and 1 light second away at the end, and thus is moving toward me at .41 light seconds/s.

My question is: What would I measure as the speed of Ship B? Would it be greater than c?

Something I just realized is that I suppose my rotational velocity is not constant. It would have to be accelerating to keep Ship A stationary with respect to the x component of its vector.
 
  • #6
:rolleyes:

Sorry, I have not yet had my coffee for the day. What I meant was a right triangle.
 

Related to Tangential Velocity, Frames, and the Speed of Light

1. What is tangential velocity?

Tangential velocity is the linear velocity of an object moving along a circular path. It is measured in units of distance per time, such as meters per second (m/s).

2. How is tangential velocity related to angular velocity?

Tangential velocity is directly proportional to the angular velocity and the radius of the circular path. This means that as the angular velocity or radius increases, the tangential velocity also increases.

3. What is a frame of reference?

A frame of reference is a set of axes or coordinate system used to measure the position, motion, and other physical quantities of an object. It is used to describe the relative motion between objects.

4. How does the speed of light relate to frames of reference?

According to Einstein's theory of relativity, the speed of light is constant in all frames of reference. This means that no matter how fast an observer is moving, they will always measure the speed of light to be the same.

5. Why is the speed of light considered to be the maximum speed in the universe?

The speed of light is considered to be the maximum speed in the universe because it is a fundamental constant and is independent of the observer's frame of reference. This means that no matter how fast an object is moving, it can never exceed the speed of light.

Similar threads

  • Special and General Relativity
Replies
25
Views
539
  • Special and General Relativity
Replies
25
Views
3K
  • Special and General Relativity
Replies
11
Views
1K
  • Special and General Relativity
Replies
8
Views
1K
  • Special and General Relativity
Replies
30
Views
3K
  • Special and General Relativity
Replies
12
Views
2K
  • Special and General Relativity
Replies
28
Views
2K
  • Special and General Relativity
Replies
6
Views
881
  • Special and General Relativity
Replies
7
Views
886
  • Special and General Relativity
2
Replies
57
Views
4K
Back
Top