- #1
paolostinz
- 25
- 1
The Problem:
A plane is dropping supplies to a clearing in the forest.
The plane will approach the clearing at an altitude of 150 m while flying level at 40 m/s. Why can't the plane drop the supplies while directly over the clearing and at what distance should it release them to arrive to its destination?
I've worked out 2 answers and I'm not entirely sure which is the correct one.
Relevant Equations:
d=vt+1/2at^2
d=1/2at^2
d=vt
The Attempt:
Solution 1
d=vt+1/2at^2
0=(40 m/s)t + 1/2(-9.8m/s^2)t^2
0=t (40 m/s - 4.9 m/s^2 t)
40 m/s = 4.9 t
t= 8.2 s
d=(40 m/s)(8.2 s)
d=328 m
Solution 2
d=1/2at^2
150 m=4.9 t^2
t= 5.5 s
d=vt
d=(40 m/s)(5.5 s)
d=220 m
Something is telling me I'm wrong/approaching this incorrectly/way off. So please, some one...help!
A plane is dropping supplies to a clearing in the forest.
The plane will approach the clearing at an altitude of 150 m while flying level at 40 m/s. Why can't the plane drop the supplies while directly over the clearing and at what distance should it release them to arrive to its destination?
I've worked out 2 answers and I'm not entirely sure which is the correct one.
Relevant Equations:
d=vt+1/2at^2
d=1/2at^2
d=vt
The Attempt:
Solution 1
d=vt+1/2at^2
0=(40 m/s)t + 1/2(-9.8m/s^2)t^2
0=t (40 m/s - 4.9 m/s^2 t)
40 m/s = 4.9 t
t= 8.2 s
d=(40 m/s)(8.2 s)
d=328 m
Solution 2
d=1/2at^2
150 m=4.9 t^2
t= 5.5 s
d=vt
d=(40 m/s)(5.5 s)
d=220 m
Something is telling me I'm wrong/approaching this incorrectly/way off. So please, some one...help!