Steady states/systems of differential equations/Phase portraits

In summary, the conversation discusses a problem with finding steady state values for a system of differential equations. The participants consider different methods for solving the problem and discuss the implications of the given information. They also mention a related but unrelated question about fish population. Ultimately, they attempt to find a solution to the initial problem by setting the derivatives to zero and determining the value of r.
  • #1
sid9221
111
0
http://dl.dropbox.com/u/33103477/2007%2010b.png

I'm can't get my head around this question, there doesn't seem to be enough information to compute a steady state ?

Any ideas on how to begin ??
 
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  • #2
Hi sid9221,

First of all, can't you solve explicitly for p(t) and r(t)? The ODE for r(t) should look very familiar.

This problem seems a bit strange. Typically to find the steady states you set ##\frac{dp}{dt} = 0## and ##\frac{dr}{dt} = 0##. These two conditions give you steady states ##(p_*, r_*)##. What do you get in this case?

It seems very fishy to me that ##\frac{dp}{dt}## and ##\frac{dr}{dt}## don't seem to depend on p at all...

Could we see part a) of the question, too?
 
  • #3
Part a) is completely unrelated.

It's some nonsense about the population of fish...
 
  • #4
sid9221 said:
Part a) is completely unrelated.

It's some nonsense about the population of fish...

The situations may be different, but are the models similar?

Did you solve for p(t) and r(t) or find the condition given by setting the derivatives to zero?
 
  • #5
http://dl.dropbox.com/u/33103477/Untitled.png
 
Last edited by a moderator:
  • #6
Thanks for posting the full problem.

Anyway, if you set ##\frac{dp}{dt}=0## and ##\frac{dr}{dt} = 0##, what must r equal?

Also, if ##r'(t) = - \beta \, r(t)##, what function must ##r(t)## be?
 

Related to Steady states/systems of differential equations/Phase portraits

1. What is a steady state in a system of differential equations?

A steady state is a point in a system of differential equations where the values of all variables remain constant over time. This means that the rate of change of these variables is equal to zero at the steady state, indicating a balance between the forces at play in the system.

2. How do you determine the stability of a steady state?

The stability of a steady state can be determined by analyzing the behavior of the system near the steady state. This involves calculating the eigenvalues of the Jacobian matrix at the steady state. If all eigenvalues have negative real parts, the steady state is stable. If any eigenvalues have positive real parts, the steady state is unstable.

3. What is a phase portrait and how is it related to a system of differential equations?

A phase portrait is a visual representation of the behavior of a system of differential equations over time. It plots the values of two or more variables against each other, with each point on the graph representing a unique combination of these variables. The shape and trajectory of the phase portrait can provide insights into the behavior and stability of the system.

4. Can a system of differential equations have multiple steady states?

Yes, a system of differential equations can have multiple steady states. These can be stable or unstable, and the behavior of the system will depend on its initial conditions and the stability of each steady state. Some systems may also have a limit cycle, where the variables oscillate between two or more steady states.

5. How can phase portraits be used to predict the long-term behavior of a system?

Phase portraits can be used to identify any stable or unstable steady states in a system, as well as limit cycles. By analyzing the direction and curvature of the trajectories in the phase portrait, it is possible to predict how the variables in the system will change over time and whether the system will reach a steady state or continue to oscillate indefinitely.

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