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kahwawashay1
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Homework Statement
A constant horizontal force F of magnitude 10N is applied to a wheel of mass 10 kg and radius 0.3 m. The wheel rolls smoothly and the acceleration of its center of mass is 0.6 m/s^2. What is that frictional force on the wheel?
The Attempt at a Solution
ok so the frictional force is static friction and assuming it rolls to the right and taking the right as positive, we have (S = static friction force):
ma=F-S
S=F-ma = 10- (10)(0.6) = 4 N
and I know that that's the right answer from my book. But can't you also find this using torques? (in the following, I=rotational inertia and R=radius, and taking clockwise as negative torque):
[itex]\tau[/itex]=I[itex]\alpha[/itex]=-SR
S= (-I/R)[itex]\alpha[/itex]
[itex]\alpha[/itex]=-a/R
I=(1/2)MR^2
S=(1/2)Ma = (1/2)(10)(0.6) = 3N ...which is not the right answer...why?
(sry meant "rotation" in title of thread not ration lol)