Is gravity the only force acting on the box? In which direction is it accelerating?goonking said:a is gravity so it is -9.8, correct?
What is the distance the box travels?goonking said:but what do i put in as x? 5, which is the length of the ramp, or 4, the base, or 3 the height?
I'm not sure what you mean by fixed, but it is friction less.Nathanael said:The ramp is fixed and frictionless, right?Is gravity the only force acting on the box? In which direction is it accelerating?What is the distance the box travels?
I mean it can't move.goonking said:I'm not sure what you mean by fixed, but it is friction less.
Nathanael said:I mean it can't move.
What direction, what distance, and with what acceleration does the block move?
It slows down the whole way. But at what rate?goonking said:the ramp is fixed.
the box goes up the ramp.
the distance it travels before flying off the ramp is 5 meters.
and I have no idea how to calculate the acceleration. I assume it slows down near the top since it is going against gravity.
Since it's frictionless, the only forces are gravity and normal force. correct? also the force from the initial pushNathanael said:It slows down the whole way. But at what rate?
Have you tried drawing a free body diagram? What are all the forces acting on the block?
Right, but the force from the initial push is irrelevant. We can "start our clocks" immediately after that force stops; when the block is moving at 12 m/sgoonking said:Since it's frictionless, the only forces are gravity and normal force. correct? also the force from the initial push
direction of normal force is perpendicular to the surface.Nathanael said:Right, but the force from the initial push is irrelevant. We can "start our clocks" immediately after that force stops; when the block is moving at 12 m/s
What is the size and direction of the normal force? And what is the net force that results from adding gravity and the normal force together?
I edited out my posit made no sense, to have Fg, we need the mass of the object, and that isn't given.Nathanael said:Yes but it's time to get into equations: What is the size of the normal force? More importantly, what is the size of the net force?
but it should be cos theta = Fg⊥ to surface divided by Fg. correct?Nathanael said:Yes but it's time to get into equations: What is the size of the normal force? More importantly, what is the size of the net force?
Maybe all hope is not lost, just continue as normal. The mass is hereby an arbitrary "m"goonking said:to have Fg, we need the mass of the object, and that isn't given.
Right, so that gives you |F⊥| = |Fg|cosθgoonking said:but it should be cos theta = Fg⊥ to surface divided by Fg. correct?
|F⊥| = |Fg|cosθ= 7.84Nathanael said:Maybe all hope is not lost, just continue as normal. The mass is hereby an arbitrary "m"Right, so that gives you |F⊥| = |Fg|cosθ
So what is the sum of the two vectors F⊥+Fg ?
No, these are vectors. They have directions. You must add them component by component. Consider the component of gravity perpendicular to the ramp... How does it combine with the normal force? What net force do they produce in the direction perpendicular to the ramp? Then what is left of gravity?goonking said:|F⊥| = |Fg|cosθ= 7.84
Fg = 9.8
so adding them is 9.8 + 7.84 = 17.64
is that correct?
The velocity of a box off a ramp can be calculated using the formula v = √(2gh), where v is the velocity, g is the acceleration due to gravity (9.8 m/s²), and h is the height of the ramp.
The angle of the ramp has a direct impact on the velocity of the box. As the angle of the ramp increases, the velocity of the box also increases. This is because a steeper ramp allows the box to gain more acceleration due to gravity.
The formula for calculating velocity of a box off a ramp assumes that the surface of the ramp is frictionless. If the surface is not frictionless, the formula will not be accurate. In this case, the frictional force must be taken into account and the formula will be v = √(2gh - μkgh), where μ is the coefficient of kinetic friction and k is the slope of the ramp.
The unit for velocity on a ramp is the same as for any other velocity measurement, which is meters per second (m/s). However, if the ramp is inclined at an angle, the velocity can also be measured in terms of horizontal distance (m) covered per unit time (s).
The mass of the box does not directly affect its velocity off a ramp. However, a heavier box will require more force to be pushed up the ramp and will therefore have a higher initial velocity. In other words, the mass of the box indirectly affects its velocity by affecting the amount of force applied to it.