- #1
Yann
- 48
- 0
I've got a simple, at least it seems so;
[tex]
\int \sqrt{9-x^2}dx
[/tex]
I MUST solve it "by parts" (withtout trigonometric substitutions), but I'm stuck. If i choose u = (9-x^2)^(1/2), du = -x/((9-x^2)^(1/2)), dv = dx, v = x. I then have;
[tex]
x\sqrt{9-x^2} + \int \frac{x^2dx}{\sqrt{9-x^2}}
[/tex]
Everything I do just make the equation more complicated. I know I have to choose another u and dv, but every choice I made only make it worse.
[tex]
\int \sqrt{9-x^2}dx
[/tex]
I MUST solve it "by parts" (withtout trigonometric substitutions), but I'm stuck. If i choose u = (9-x^2)^(1/2), du = -x/((9-x^2)^(1/2)), dv = dx, v = x. I then have;
[tex]
x\sqrt{9-x^2} + \int \frac{x^2dx}{\sqrt{9-x^2}}
[/tex]
Everything I do just make the equation more complicated. I know I have to choose another u and dv, but every choice I made only make it worse.