- #1
Miike012
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Homework Statement
If: (x/l)/(mb+nc-ax) = (y/M)/(nc+la-mb) = (z/n)/(la+mb-nc)
Prove: l/x(by+cz-ax)=m/y(cz+ax-by)=n/z(ax+by-cz)
The next line in the book says...
1. (ny+mz)/a = 2. (lz+nx)/b = 3. (mx+ly)/c
I don't understand how they got to this point...
My guess is that they added them seperatly then simplifyed somehow?
This is what I came up with after adding them...
The Attempt at a Solution
1. (y/m + z/n)/2la = 2. (z/n+x/l)/2mb = 3. (y/m+x/l)/2nc
it looks like in 1. they cross mult in the numerator whish would then give us (ny+mz/nm)/2la = (ny+mz)/(nm)2la... but where did the nm2l go in the denominator?