Solve Herstein's Abstract Algebra Problem: Can u = 4n+3 be Written as a^2 + b^2?

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In summary, the conversation is about trying to solve a problem from Herstein's Abstract Algebra where u cannot be written in the form of a^2 + b^2, given that u = 4n + 3 and a and b are both natural numbers. The person asking for help provides a hint that involves considering the remainders when dividing a^2 + b^2 by 4, and suggests that one of a and b must be odd while the other is even. The person seeking help thanks them and decides to try again.
  • #1
JasonRox
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This isn't homework, but I'll post it anyways because I'd like to know.

It's from Herstein's Abstract Algebra.

Show that if u = 4n + 3, where [itex]n\inN[/itex], then you can not write u in the from u = a^2 + b^2, where [itex]a,b\inN[/itex].

I feel silly for asking this, but I'm curious to know.

The one thing I do, which is obvious is that if a is odd, then b is even because u is odd. But I don't think you need this fact to solve it.

Any directions?

Please do not post solutions!
 
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  • #2
JasonRox said:
This isn't homework, but I'll post it anyways because I'd like to know.

It's from Herstein's Abstract Algebra.

Show that if u = 4n + 3, where [itex]n\inN[/itex], then you can not write u in the from u = a^2 + b^2, where [itex]a,b\inN[/itex].

I feel silly for asking this, but I'm curious to know.

The one thing I do, which is obvious is that if a is odd, then b is even because u is odd. But I don't think you need this fact to solve it.

Any directions?

Please do not post solutions!
Okay, I'll give you a hint:
So one of a, and b must be odd, and the other is an even number, right?
So let a = 2k, b = 2x + 1 (k, x are all integers).
Now what's a2 + b2? If you divide a2 + b2 by 4, what's the remainder?
You can take it from here, right? :)
 
  • #3
VietDao29 said:
Okay, I'll give you a hint:
So one of a, and b must be odd, and the other is an even number, right?
So let a = 2k, b = 2x + 1 (k, x are all integers).
Now what's a2 + b2? If you divide a2 + b2 by 4, what's the remainder?
You can take it from here, right? :)

That's exactly what I did!

I knew something wasn't right when I was looking at it.

I'll give it another shot thanks.
 

Related to Solve Herstein's Abstract Algebra Problem: Can u = 4n+3 be Written as a^2 + b^2?

1. Can the equation u = 4n+3 be solved for all values of n?

Yes, the equation can be solved for all values of n, as long as u is a positive integer.

2. What is the significance of using the variable u in the equation instead of n?

The variable u represents the sum of two squares, a^2 + b^2. This allows us to use properties of Pythagorean triples to solve the equation.

3. How do you approach solving this problem?

The problem can be solved by using the fact that every positive integer can be written as the sum of two squares, and then manipulating the equation to fit that form.

4. What is the relationship between this problem and Pythagorean triples?

The equation u = 4n+3 is related to Pythagorean triples because it can be written in the form of a Pythagorean triple, where u is the sum of two squares. This allows for the use of Pythagorean triple properties to solve the equation.

5. Are there any real-world applications for solving this problem?

This problem has applications in cryptography and number theory. It can also be used to prove theorems in abstract algebra and explore the properties of Pythagorean triples.

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