Simple jordan canonical form question

In summary, for the second part, we can find bases of R3 with respect to which Q-1AP represents the mapping x|->Ax by either multiplying the standard basis vectors with Q-1 or by taking the columns of Q-1AP as basis vectors.
  • #1
franky2727
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two part question to which i have answered the first part and am stuck on the 2nd part
find r and invertible real matrices Q and P such that Q-1AP=(Ir,0),(0,0)
where each 0 denotes a matrix of zeroes(not necessarily the same size in each case)

second part being paying special attention to the order of the vectors, write down bases of R3 with respect to which Q-1AP represents the mapping x|->Ax

answers to the first part are r=1 Q-1=(100),(-210),(-301) and therefore Q=(100),(1/2,1,0),(1/3,0,1)
and P=(1-21),(010),(000)
can show the working for this if you want but don't think its required for the second part, however i have no idea where to start with the 2nd part and would apprechiate a shove in the right direction, thanks
 
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  • #2


For the second part, we need to find bases of R3 that represent the mapping x|->Ax.

First, let's consider the basis of R3 given by the standard basis vectors: e1=(1,0,0), e2=(0,1,0), e3=(0,0,1).

We can represent these basis vectors in terms of the new basis vectors by multiplying them with Q-1:
Q-1e1 = (1,1/2,1/3), Q-1e2 = (0,1,0), Q-1e3 = (0,0,1).

These vectors form a basis for R3 with respect to which Q-1AP represents the mapping x|->Ax.

Another way to find a basis is to consider the columns of Q-1AP. The first column (1,0) represents the mapping x|->Ax1, where x1 is the first column of x. Similarly, the second column (0,0) represents the mapping x|->Ax2, where x2 is the second column of x.

So, we can take the basis vectors for R3 to be the columns of Q-1AP:
(1,0,0) and (0,0,1).

Note that these two bases are not unique, there are infinitely many bases that can represent the mapping x|->Ax. These are just two examples.
 

Related to Simple jordan canonical form question

1. What is the purpose of the simple Jordan canonical form?

The simple Jordan canonical form is used to simplify a matrix into a block diagonal form, making it easier to calculate its properties and perform operations on it. It also helps to identify the eigenvalues and corresponding eigenvectors of a matrix.

2. How is the simple Jordan canonical form different from the standard Jordan canonical form?

The simple Jordan canonical form only considers the invariant factors of a matrix, while the standard form also includes the multiplicity of each factor. This makes the simple form more concise and easier to work with.

3. Can all matrices be transformed into a simple Jordan canonical form?

No, not all matrices have a simple Jordan canonical form. For a matrix to have a simple form, it must be diagonalizable and have distinct eigenvalues.

4. How is the simple Jordan canonical form calculated?

The simple Jordan canonical form is calculated by finding the invariant factors of a matrix, which are the elementary divisors of the matrix. These divisors are then arranged in a block diagonal form to create the simple Jordan canonical form.

5. What is the significance of the simple Jordan canonical form in linear algebra?

The simple Jordan canonical form is an important tool in linear algebra as it simplifies the calculation of properties such as the determinant, eigenvalues, and eigenvectors of a matrix. It also helps in solving systems of linear equations and performing transformations on matrices.

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