You're off by a factor of 10.hermy said:1 = 2 pi (m/0.1)1/2
1 = 4 pi2 m/0.1
solving this, m= 25 grams
You are assuming that the period is 1 second. Was that specified in the problem? (Was information given about the pendulum?)The answer is supposed to be 10 grams. What is wrong in my solution?
Simple harmonic motion is a type of periodic motion where a system oscillates back and forth around an equilibrium point with a constant amplitude and frequency.
A pendulum in a clock works by converting potential energy into kinetic energy as it swings back and forth. The length of the pendulum and the force of gravity determine the period of the pendulum's oscillation.
Yes, a spring-mass system can exhibit simple harmonic motion if the spring is ideal (massless and frictionless) and the mass attached to the spring follows Hooke's Law (the force is directly proportional to the displacement).
If a pendulum in a clock was replaced by a spring-mass system, the clock would still keep accurate time as long as the spring-mass system exhibits simple harmonic motion with the same period as the pendulum. However, the design and mechanism of the clock would need to be adjusted to accommodate the change.
The amplitude of simple harmonic motion is the maximum displacement from the equilibrium point, and the frequency is the number of oscillations per unit time. The amplitude and frequency both affect the energy and period of the motion, with a larger amplitude resulting in more energy and a smaller frequency resulting in a longer period.