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fluffymastr
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Homework Statement
A 5g bullet is fired horizontally into a 0.50kg block of wood resting on a frictionless table. The block, which is attached to a horizontal spring, retains the bullet and moves forward, compressing the spring. The block-bullet system goes into SHM with a frequency of 9Hz and amplitude of 15cm.
A) Determine the speed of the bullet
Homework Equations
Fs=-kx
a=-(k/m)x
PEs= .5kx2
v=±[(k/m)(A2-x2)].5
T=2π(m/k).5
The Attempt at a Solution
I wasn't sure how to even approach this but I think I need to determine the spring constant k using a form of T=2π(m/k).5.
So:
T=2π(m/k).5
T2=4π2(m/k)
T2=4π2(m/k)
k=(4π2m)/(T2)
k=(4π2(.5kg+.005kg))/(92)
k=.24613kg/s2
Then plug that into:
v=±[(k/m)(A2-x2)].5
v=±[(.24613/.505)(.152-02)].5
v=.1047m/s
I have NO IDEA if I am right or not. Anyone want to confirm or deny?