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kelly0303
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Hello! Is there any simple (i.e. using some physics arguments, without actually doing the math) explanation for why $$\sigma(pp \to \pi^+d)/\sigma(np\to\pi^0d)=2$$ where d is the deuteron? Thank you!
Thank you! yes, i would like something like that, based on some symmetries, rather than actually blindly calculating some feynman diagrams.Gaussian97 said:Well, what do you mean with "no math" there is a way to deduce using isospin symmetry and little assumptions. If you compare the amount of math of this method compared with the actual computation of a cross-section, this is almost without maths, but you still need some mathematical knowledge of the representations of SU(2) group. Is that what you want?
A cross section ratio is a comparison of the area of a cross section of one object to the area of a cross section of another object. It is often used in physics and engineering to describe the relative sizes of different objects or to calculate probabilities in particle interactions.
A cross section ratio is calculated by dividing the area of the cross section of one object by the area of the cross section of the other object. The units of the cross section ratio will depend on the units used for the areas of the cross sections.
A cross section ratio is important because it allows us to compare the sizes of different objects or to calculate the likelihood of particle interactions. It is also used in many scientific and engineering applications, such as in fluid dynamics and material science.
A cross section ratio is a comparison of two cross section areas, while a cross section area is the area of a single cross section. The cross section ratio provides a relative measure, while the cross section area gives an absolute measure.
Yes, a cross section ratio can be greater than 1. This indicates that the area of the cross section of one object is larger than the area of the cross section of the other object. A cross section ratio of 1 would indicate that the two objects have equal cross section areas.