Rotating Disk and two students?

In summary: I never opposed the results.Yes I agree that it will be the same for both the cases. However there need to be linguistic distinction if we wish to report our results. Isn't it? All I opposed what Maximum Physics gave the reason of... it was not satisfactory. I never opposed the results.In summary, the conversation discusses a physics problem involving students walking on a rotating disc and the resulting decrease in the disc's rate of rotation. There is some disagreement about the reason for this decrease, with one person suggesting it is due to the students' force on the disc and another pointing to the net torque being applied. The importance of making free body diagrams and thoroughly understanding the question is emphasized.
  • #1
MaximumPhysics
7
0

Homework Statement



sMwUC5o.png


Homework Equations



Read below

The Attempt at a Solution



A) D. As the mass of the students gets further away from the axis of rotation, the rate slows down (remember the skater with arms out).
B) T. No explanation currently...
C) ?
D) T. The students exert a force on the plate (and the plate on the students) when walking out. Thus, that force over the distance walked causes word to be down. Consequently the force of the plate on the students is what slows the rotation rate.
E) S. Angular momentum is conserved.

Have no idea about C I tried both T or F.

DTFTS and DTTTS
 
Physics news on Phys.org
  • #2
What is your explanation for (B). I mean you must have at least thought of something while saying its true which however it is not. Consider this. Take your disc as one system and the two students as one system. If there is no net torque on the disc, why is it slowing down? Moreover try drawing Free Body Diagrams of each element of your disc+students system; you will know what I am talking about.
Moreover, your explanation for (A) is unsatisfactory. You must know why the rate of rotation decreases. Its not like you know similar situation where it decreases, so it must decrease in this case as well. You must be 100 % sure and must be able to explain why while you give your response.
For (C), moment of inertia about the axis perpendicular to the plane is given by $$ J = ∫r^2 dm $$ I think that will give you an idea.
(D) As a matter if fact, when you will analyse the free body diagrams, you will notice that there is no net force exerted by the two students system on the disc. However, you do know that even torque might do work. So figure this out yourself.
(E) Yes that is correct.

And I will advise you to make free body diagrams while solving problems. It is an important tool. Further if you say something, you must be able to prove it. If you cannot answer why, don't use it.
 
  • #3
Vatsal Sanjay said:
there is no net force exerted by the two students system
To be fair, MaximumPhysics didn't say there was. The statement
MaximumPhysics said:
The students exert a force on the plate
can be read as referring to each student individually.
 
  • #4
Ya each "student" will exert force on the disc. However this force is not the reason for slowing down of the disc. Net force applied by the "students" is zero but not the net torque. So there is no point talking about this force. And the question cleary asks about students doing work not about each student. Please pardon me but i hate manipulation of words in physics
 
  • #5
Vatsal Sanjay said:
Ya each "student" will exert force on the disc. However this force is not the reason for slowing down of the disc. Net force applied by the "students" is zero but not the net torque. So there is no point talking about this force. And the question cleary asks about students doing work not about each student. Please pardon me but i hate manipulation of words in physics
Most of my mistakes in physics are due to manipulation of words.
Some time I feel that I have to memorize the question and the answer instead of understanding it.

English is not my first language, so those kind of questions always get me in trouble.

Do you know of any way where I can strength my ability in those type of questions where they play with words?
 
  • #6
MaximumPhysics said:
Do you know of any way where I can strength my ability in those type of questions where they play with words?
Yes there is one way. Take every word of a question by its face value or literal meaning. What I mean is, students means students. If they wanted to ask about individual student they must have mentioned each student or individual student. See if you take every word of the question by what it says and then there is some hidden meaning or manipulation, that is not your fault. You need not worry about it.
 
  • #7
Vatsal Sanjay said:
Yes there is one way. Take every word of a question by its face value or literal meaning. What I mean is, students means students. If they wanted to ask about individual student they must have mentioned each student or individual student. See if you take every word of the question by what it says and then there is some hidden meaning or manipulation, that is not your fault. You need not worry about it.

Thanks and I believe I am still stuck, but I believe DTFTS is correct I can't see any other answer.

Could you tell me what I have incorrect? last 2? first 2?
 
  • #8
Vatsal Sanjay said:
each "student" will exert force on the disc. However this force is not the reason for slowing down of the disc.
Yes it is. It doesn't matter whether you consider the effect of each force separately and add them, or combine them into a torque. Either way slows the disc just the same. We could have had one student moving out first, then the other, to get the same result.
Vatsal Sanjay said:
the question cleary asks about students doing work not about each student.
You are making a linguistic distinction where none exists. Both readings are valid. Fortunately, the work done cannot depend on whether you analyse separately and add or treat them as a unit. The only place in the questions where it matters is B, and there it makes clear it is concerned with the net of the forces.
MaximumPhysics said:
I believe DTFTS is correct
No. As Vatsal asked, please give your reasoning for your answer on B.
 
  • #9
haruspex said:
Fortunately, the work done cannot depend on whether you analyse separately and add or treat them as a unit
Yes I agree that it will be the same for both the cases. However there need to be linguistic distinction if we wish to report our results. Isn't it? All I opposed what Maximum Physics gave the reason of his answer and also the fact he has no where mentioned about the torque on the disc.
 
  • #10
MaximumPhysics said:
Thanks and I believe I am still stuck, but I believe DTFTS is correct I can't see any other answer.
Dude! If you trying to match your answer with some answer script, I must tell you that those are not always correct. Form your own answers and whatever you write, you must know the proper reason behind it. If you can prove what you are saying, you are correct.
 
  • #11
Vatsal Sanjay said:
Yes I agree that it will be the same for both the cases. However there need to be linguistic distinction if we wish to report our results. Isn't it? All I opposed what Maximum Physics gave the reason of his answer and also the fact he has no where mentioned about the torque on the disc.
There is a problem with the proposed answer to D, but it's that MaximumPhysics has not shown that each student exerts a force in (or at least, partly in) the direction of movement.
 
  • #12
Obviously there is a problem with his answer to D) That is why I am asking him to re analyse his solution.
 

Related to Rotating Disk and two students?

1. What is a rotating disk experiment?

A rotating disk experiment involves a disk that is spun at a constant speed while students measure and analyze the effects of centripetal force on objects placed on the disk.

2. How does centripetal force affect objects on the rotating disk?

Centripetal force causes objects on a rotating disk to move in a circular path instead of a straight line, as the force is constantly pulling the objects towards the center of the disk.

3. What are some common variables that can be manipulated in a rotating disk experiment?

Common variables that can be manipulated in a rotating disk experiment include the speed of the disk, the mass and size of the objects placed on the disk, and the distance from the center of the disk to the objects.

4. How do you measure the centripetal force in a rotating disk experiment?

The centripetal force can be measured using a spring scale attached to the objects on the disk, which will show the force exerted on the objects as they move in a circular path.

5. What are the real-world applications of a rotating disk experiment?

Rotating disk experiments can help us understand the effects of centripetal force in various scenarios, such as amusement park rides, satellite orbits, and the motion of planets around the sun. They also have practical applications in industries such as engineering and physics.

Similar threads

  • Introductory Physics Homework Help
Replies
30
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
28
Views
3K
  • Introductory Physics Homework Help
Replies
5
Views
800
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
24
Views
2K
  • Introductory Physics Homework Help
Replies
16
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
755
  • Introductory Physics Homework Help
Replies
9
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
Back
Top