- #1
Marshillboy
- 21
- 0
Homework Statement
http://img138.imageshack.us/img138/6717/hwprob.jpg
Homework Equations
General intuition, KCL, KVL
The Attempt at a Solution
I've worked this out multiple ways to no avail. I think the easiest way to go about this is to set the left node to ground (0 potential) and go from there.
EDIT: Using the assumption that my first statement below is correct, I found the solution of -46V. My second question still holds though.
Here are a few things that none of my professors or TAs have been clear on:
1) When you have current through a resistor (such as Io), using Ohm's law you then know the voltage. Something I'm very unclear on is which way the voltage drops across the resistor. In my class, we use current from positive -> negative as dissipated power with a positive sign (like in a resistor), and negative to positive as a source, with a negative sign. Does this mean that the potential at the bottom node is -2V?
2) How can you have a potential across an ideal current source when the component doesn't have a resistance?
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