- #1
Zak
- 15
- 0
If say you have some scalar field, θ(x^u), where x^u represents the 4-vector coordinates of spacetime, and then the typical classical equation of motion, a = -∇θ, how would one go about 'generalizing' this to a relativistic version? Since F = ma, would you have to write it as d/dt (P^u) where P^u is the relativistic 4-momentum? But since P^0 = m, this means that the 0 component of the 4-vector simply vanishes, and this seems unsatisfactory to me since you're essentially just keeping everything Newtonian. Can anybody shed some light on this?
(sorry for the bad notation)
Thanks in advance
(sorry for the bad notation)
Thanks in advance