omari_yousef said:Equation (p=i^2 * R) seems to suggest that the rate of increase of thermal energy in a resistor is reduced if the resistance is made less.
"Eq" : p =v^2/R seems to suggest just the apposite .
How do you reconcile this apparent paradox?
The relation between resistance and power dissipation is that as resistance increases, power dissipation also increases. This is because resistance is the measure of opposition to the flow of electric current, and as the current encounters more resistance, more energy is converted into heat, resulting in higher power dissipation.
Resistance affects power dissipation in a circuit by causing a voltage drop. When current flows through a resistor, some of the electrical energy is converted into heat, and this energy is dissipated from the circuit. The amount of power dissipated is directly proportional to the resistance in the circuit.
Resistance has a greater impact on power dissipation than current. While both factors play a role in determining the amount of power dissipated in a circuit, resistance has a direct relationship with power dissipation, while current has an indirect relationship. This means that a small change in resistance can have a larger impact on power dissipation than the same change in current.
Resistance can be reduced to decrease power dissipation by using materials with lower resistivity, increasing the surface area of the conductive material, or using thicker wires. Additionally, minimizing the length of the circuit and avoiding sharp bends in the wires can also help reduce resistance and therefore decrease power dissipation.
Understanding the relation between resistance and power dissipation is important in designing and optimizing electrical circuits, as well as in choosing appropriate materials for various applications. For example, in electronic devices, minimizing power dissipation can help prolong battery life and prevent overheating, while in power systems, managing resistance can help improve efficiency and reduce energy waste.