Range of projectile launched from a non-rotating spherical planet

  • #1
greyhound
4
0
TL;DR Summary
Let's assume we have a non-rotating planet of radius R and we launched a projectile with initial speed v_0 at angle theta to the tangent plane to the surface. Let's further simplify the situation by assuming that we have constant magnitude acceleration of g. What would be the "range" of the projectile? That is, how far away along the surface from the launch point would the object land?
I figured this would be a problem in some classical mechanics book but so far I can't find an answer anywhere. Assume there is no drag or lift, and since the planet is not rotating we don't have to worry about Coriolis effects. I'm working on a solution but I want to see if my work is correct. Surely this is a problem somewhere? Any one got an answer?
 
Physics news on Phys.org
  • #2
greyhound said:
TL;DR Summary: Let's assume we have a non-rotating planet of radius R and we launched a projectile with initial speed v_0 at angle theta to the tangent plane to the surface. Let's further simplify the situation by assuming that we have constant magnitude acceleration of g. What would be the "range" of the projectile? That is, how far away along the surface from the launch point would the object land?

I figured this would be a problem in some classical mechanics book but so far I can't find an answer anywhere. Assume there is no drag or lift, and since the planet is not rotating we don't have to worry about Coriolis effects. I'm working on a solution but I want to see if my work is correct. Surely this is a problem somewhere? Any one got an answer?
You say constant magnitude of ##g##, but what about direction?

Also, you must show your work if you are to receive help. The reason to withhold your work is?
 
  • #3
Basically I'm assuming that gravity points towards the planet's centre i.e. ##\vec{a}=-g\hat{r}##. You know what, let's the situation and assume that the projectile is shot tangentially to the planet's surface. The reason why I haven't posted any work is that I'm still working on it. I just want to check my answer when I finish it. This isn't for homework or anything, I'm just curious about it. I thought it would be a problem in some classical mechanics book but I can't find anything like it anywhere. I'm at work right now, I'll post what work I have later.

I just wanted to see if anyone happened to know the answer. It seems like a doable question and I'm surprised that I can't find the answer. Or perhaps it's not so doable and that's why I can't find the answer. One thing about it is that it's bugging me and I want to work on it.
erobz said:
You say constant magnitude of ##g##, but what about direction?

Also, you must show your work if you are to receive help. The reason to withhold your work is?
 
  • #4
greyhound said:
Basically I'm assuming that gravity points towards the planet's centre i.e. ##\vec{a}=-g\hat{r}##. You know what, let's the situation and assume that the projectile is shot tangentially to the planet's surface. The reason why I haven't posted any work is that I'm still working on it. I just want to check my answer when I finish it. This isn't for homework or anything, I'm just curious about it. I thought it would be a problem in some classical mechanics book but I can't find anything like it anywhere. I'm at work right now, I'll post what work I have later.

I just wanted to see if anyone happened to know the answer. It seems like a doable question and I'm surprised that I can't find the answer. Or perhaps it's not so doable and that's why I can't find the answer. One thing about it is that it's bugging me and I want to work on it.
It seems to me that some initial velocity could send it into orbit?
 
  • #5
I think with your simplification of a constant radial force and a good choice of coordinates, the answer follows fairly straightforwardly. I get ##d=\frac{2 v_0^2 \cos(\theta) \sin(\theta)}{g}##.

EDIT: Of course, I could have made all kinds of errors, so my answer may be meaningless without the steps :smile:

EDIT2: Yes, many errors. The above is almost certainly wrong. It assumes the angular velocity is a constant.
 
Last edited:
  • #6
Haborix said:
I think with your simplification of a constant radial force and a good choice of coordinates, the answer follows fairly straightforwardly. I get ##d=\frac{2r_0 v_0^2 \cos(\theta) \sin(\theta)}{g}##.
I think there might be an issue with your equation. It looks like your answer for range would have units of length##^2##.
 
  • #7
greyhound said:
I think there might be an issue with your equation. It looks like your answer for range would have units of length##^2##.
Yeah, I fixed that, but not quick enough!
 
  • #8
Hopefully you can make out the situation below, but that's what I'm looking for. I'm assuming that ##v_0## is small so that it doesn't orbit. I figure the path will fit an ellipse. I'm just wondering what the equation of motion is for this situation.
Range.png
 
  • #9
greyhound said:
Hopefully you can make out the situation below, but that's what I'm looking for. I'm assuming that ##v_0## is small so that it doesn't orbit. I figure the path will fit an ellipse. I'm just wondering what the equation of motion is for this situation.
View attachment 343671
I'm taking a look at my answer again. I think I might have gotten all my angles muddled up.
 
  • #10
Without an atmosphere, I would expect the projectile to follow an elliptical path, a partial orbit, with the near focus at the centre of the planet.
 
  • Like
Likes greyhound
  • #11
greyhound said:
Hopefully you can make out the situation below, but that's what I'm looking for. I'm assuming that ##v_0## is small so that it doesn't orbit. I figure the path will fit an ellipse. I'm just wondering what the equation of motion is for this situation.
View attachment 343671
I'm getting a system of second order nonlinear ODE's using Newtons Laws in polar coordinates. I'm trying to find ##r(\theta)##. Maybe I'm missing the bigger picture though.
 
  • Like
Likes Haborix
  • #12
erobz said:
I'm getting a system of second order nonlinear ODE's using Newtons Laws in polar coordinates. I'm trying to find ##r(\theta)##. Maybe I'm missing the bigger picture though.
That's the kind of mess I'm getting as well now that I worked through it more carefully. Even with the simplification on the functional form for gravity, I don't think there will be a nice closed form solution for the range.
 
  • Like
Likes erobz
  • #13
Close as I (think) can get for the ODE that would yield ##r(t)## (the radial coordinate- not range):

$$ \ddot r - \frac{v_o^2R^2}{r^3} = -g $$

I don't know how to progress on that( analytically).
 
Last edited:
  • Like
Likes greyhound
  • #14
erobz said:
Close as I (think) can get for the ODE that would yield ##r(t)## (the radial coordinate- not range):

$$ \ddot r - \frac{v_o^2R^2}{r^3} = -g $$

I don't know how to progress on that.
That's what I got. And then you would need to solve for the time from ##r(t_f)=R##. With that time you could integrate the relationship ##r^2\dot{\phi}=R v_o\sin(\theta)## to get the difference in azimuthal angle from the starting position to the final position. Multiplying that angle by ##R## would give you the range.
 
  • Like
Likes erobz

Similar threads

Replies
4
Views
872
  • Introductory Physics Homework Help
Replies
17
Views
2K
  • Sci-Fi Writing and World Building
Replies
0
Views
764
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Astronomy and Astrophysics
Replies
2
Views
1K
  • Sci-Fi Writing and World Building
Replies
10
Views
2K
Back
Top