- #1
ClaireBear1596
- 9
- 0
I have a particle in a spherical well with the conditions that V(r) = 0 is r < a, and V(r) = V0 if r ≥ a.
In this problem we are only considering the l=0 in the radial equation.
After solving this I found that in the region 0<r<a, u(r)=Bsin(kr) (k=√2mE/hbar), and in the other region, u(r)=Bexp(-la) (l=√2m(E+V0/hbar). I was supposed to show that in order to find E I needed to solve a transcendental equation of the form sinθ=±ςθ, however my result was l=ktan(ka), so I am unsure what to do with this.
Also, I was wondering why is it that there is a possibility of there being no bound states if V0 is too small? And how would I go about finding this minimum potential?
Thanks!
In this problem we are only considering the l=0 in the radial equation.
After solving this I found that in the region 0<r<a, u(r)=Bsin(kr) (k=√2mE/hbar), and in the other region, u(r)=Bexp(-la) (l=√2m(E+V0/hbar). I was supposed to show that in order to find E I needed to solve a transcendental equation of the form sinθ=±ςθ, however my result was l=ktan(ka), so I am unsure what to do with this.
Also, I was wondering why is it that there is a possibility of there being no bound states if V0 is too small? And how would I go about finding this minimum potential?
Thanks!