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syj
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Homework Statement
PROVE:
If A(t) is nxn with elements which are differentiable functions of t
Then:
[itex]\frac{d}{dt}[/itex](det(A))=[itex]\sum[/itex]det(Ai(t))
where Ai(t) is found by differentiating the ith row only.
Homework Equations
I know I should prove this by induction on n
The Attempt at a Solution
Consider the matrix A1 being a 1x1 matrix
So n=1
the derivative of the determinant is the same as the derivative of that one row, therefore the theorem holds for n=1
assume the proof will hold true for n=k call this matrix Ak
now prove the theorem holds true for n=k+1
[itex]\frac{d}{dt}[/itex](det(Ak+1)) =[itex]\frac{d}{dt}[/itex](det(A1)+[itex]\frac{d}{dt}[/itex](det(Ak))
AND
[itex]\sum[/itex](det(Ak+1) = [itex]\sum[/itex]det(A1)+[itex]\sum[/itex]det(Ak)
Is this it?
have I proved it?