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spacecadette
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Firemen are shooting a stream of water at a burning building using a high-pressure hose that shoots out the water with a speed of 25.0 {\rm m/s} as it leaves the end of the hose. Once it leaves the hose, the water moves in projectile motion. The firemen adjust the angle of elevation \alpha of the hose until the water takes 3.00 {\rm s} to reach a building 45.0 {\rm m} away. You can ignore air resistance; assume that the end of the hose is at ground level.
I found the following:
angle a = 53.1
speed of water at highest point = 15m/s
magnitude of acceleration at highest point = 9.8m/s^2
I need to find:
How high above the ground does the water strike the building?
How fast is it moving just before it hits the building?
I tried using V^2 - Voy^2 = -2g(y-yinitial)
I can't seem to get the right answer.
I found the following:
angle a = 53.1
speed of water at highest point = 15m/s
magnitude of acceleration at highest point = 9.8m/s^2
I need to find:
How high above the ground does the water strike the building?
How fast is it moving just before it hits the building?
I tried using V^2 - Voy^2 = -2g(y-yinitial)
I can't seem to get the right answer.