- #1
katielynn09
- 6
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A ball is projected horizontally from the edge
of a table that is 0.823 m high, and it strikes
the floor at a point 1.44 m from the base of
the table.
The acceleration of gravity is 9.8 m/s2 .
What is the initial speed of the ball? An-
swer in units of m/s.
the table is .823 m high.
x = xo + vot+ .5at^2
x = .823 , xo = 0, vot = 0 (vertical speed is 0), a = 9.8 m/s2 and you solve for t
.823 m = .5(9.8 m/s2)t^2
t^2 = .1679 s
t = .41 sec
to find the intial speed you know the distance and the time
x = xo +vot+.5at^2
1.44 m = 0 m + vo(.41 s) + .5(9.8 m/s2)(.41 s)^2
you get vo = 1.5 m/s
I tried this but I did something wrong because i enter my homework online and it told me the answer i got was incorrect.
of a table that is 0.823 m high, and it strikes
the floor at a point 1.44 m from the base of
the table.
The acceleration of gravity is 9.8 m/s2 .
What is the initial speed of the ball? An-
swer in units of m/s.
the table is .823 m high.
x = xo + vot+ .5at^2
x = .823 , xo = 0, vot = 0 (vertical speed is 0), a = 9.8 m/s2 and you solve for t
.823 m = .5(9.8 m/s2)t^2
t^2 = .1679 s
t = .41 sec
to find the intial speed you know the distance and the time
x = xo +vot+.5at^2
1.44 m = 0 m + vo(.41 s) + .5(9.8 m/s2)(.41 s)^2
you get vo = 1.5 m/s
I tried this but I did something wrong because i enter my homework online and it told me the answer i got was incorrect.
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