- #1
bobey
- 32
- 0
Homework Statement
the question :
integrate the following :
integration of d(y/x) = integration of(c cos x/x^2) dx , where c is a constant
Homework Equations
integration of d(y/x) = integration of(c cos x/x^2) dx
y/x = c integration of (c cos x/x^2) dx (*)
= c(x^-2 sin x -integration(sin x (-2x^-3))dx
(*) i let u = x^-2
du = -2x^-3
dv= cos x dx
v = sin x
and by integration by parts, i got (*)
but the integration on the RHS seems to complex which contradicts with the principle of integration by parts, which makes the integration simpler... i think i made some mistake some where... can anyone highlight it to me... please...