- #1
Alain12345
- 37
- 0
A person standing at the base of a building throws a stone straight up at 40 m/s. If the building is 35 m high, calculate:
a) The maximum height to which the stone will rise
b) How long it would take for the stone to land on the roof
c) The velocity at which the stone would hit the roof
I was only able to calculate a (I got -81.6m). It took 4.08 s for the stone to get to that height. I have no clue how to get b and c. If the distance from the max height to the roof is 46.6 m, the acceleration is 9.81 m/s2, and V1 is 0m/s, I can't find a way to calculate V2 and the time.
a) The maximum height to which the stone will rise
b) How long it would take for the stone to land on the roof
c) The velocity at which the stone would hit the roof
I was only able to calculate a (I got -81.6m). It took 4.08 s for the stone to get to that height. I have no clue how to get b and c. If the distance from the max height to the roof is 46.6 m, the acceleration is 9.81 m/s2, and V1 is 0m/s, I can't find a way to calculate V2 and the time.