Principal Quantum Number of the Excited Oxygen atom.

In summary, the conversation discusses the use of quantum numbers to describe the state of electrons in atoms and molecules. It is pointed out that it is not accurate to assign a quantum number to an entire atom or molecule, as these numbers only describe the state of individual electrons. The example of oxygen's excited state is used to illustrate this concept.
  • #1
acinbat
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Normally, Oxygen has 8 electrons in its neutral form that is 1s2 2s2 2p4. In this case, its principal quantum number (n) is two.

But what happens if it got excited and its electronic configuration becomes 1s2 2s2 2p3 3s1? In this case, Is the principal quantum number (n) of oxygen two or three?

Thanks.
 
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  • #2
Quantum numbers are used to describe the state(s) of electrons not whole atoms AFAIK. You may be referring to the fact that many Chemists will refer to things such as 2p elements etc, this is really just a reference to their place in the periodic table which may be useful in certain conversations.

It really doesn't make sense to give a quantum number to an entire atom/molecule as these numbers are used to describe the state of the electron(s) in an atom/molecule. For instance a 1s electron has n=1 (principle quantum number), l=0, ml=0 and ms= +/- 1/2. A 2s electron will have the same numbers except n=2. A 2p electron is n=2; l=0,1; ml=-1, 0, 1 and ms=+/- 1/2.

One more thing to keep in mind is that Oxygen is diatomic, meaning its elemental form is O2 so a description using atomic orbitals is severely lacking. A more thorough description of Oxygen and its excited states should make use of molecular orbital theory.
 
  • #3
Oh, you are right. I should have asked like this: the electron of oxygen atom that is denoted by n=2, l=1 transferred to n=3, l=0 after the excitation process. At this moment, what is the electron's principal quantum number, two or three? But I think I got it after your message. It will be three.
 
  • #4
I also misspoke actually. A 2p electron would have n=2, l=1, ml=-1,0,1 and ms=+/- 1/2. Mistake being that the letter "p" denotes the azimuthal quantum number (l) of 1.
 
  • #5


In this case, the principal quantum number (n) of the excited oxygen atom would be three. This is because the principal quantum number represents the energy level of the electron, and in the excited state, the electron has moved from the 2p orbital to the 3s orbital, indicating an increase in energy level. Therefore, the principal quantum number would also increase from 2 to 3. Additionally, the number of electrons in the 3s orbital (1) also corresponds to the principal quantum number, further confirming that n is now three.
 

Related to Principal Quantum Number of the Excited Oxygen atom.

1. What is the principal quantum number of the excited oxygen atom?

The principal quantum number, denoted by n, represents the energy level or shell of an electron in an atom. For an excited oxygen atom, n can take values from 2 to 6, depending on the level of excitation.

2. How does the principal quantum number affect the energy of the excited oxygen atom?

The higher the value of n, the higher the energy level and the more distant the electron is from the nucleus. This means that the excited oxygen atom with a higher principal quantum number will have a higher energy than one with a lower n value.

3. What is the relationship between the principal quantum number and the size of the excited oxygen atom?

The size of an atom is determined by the average distance of the outermost electron from the nucleus. As the principal quantum number increases, the size of the excited oxygen atom also increases, as the electron is found farther from the nucleus.

4. Can the principal quantum number of an excited oxygen atom change?

Yes, the principal quantum number can change if the atom undergoes an energy transition. This can occur when the atom absorbs or emits energy, causing the electron to move to a different energy level.

5. How is the principal quantum number of an excited oxygen atom related to its spectral lines?

The principal quantum number determines the energy difference between the energy levels of an excited oxygen atom. When the electron transitions between these levels, it emits or absorbs a specific amount of energy, resulting in spectral lines. The higher the principal quantum number, the greater the energy difference and the more energetic the spectral lines.

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