Pressure drop for viscous fluid in conducts with an obstacle at the outlet

In summary, the pressure drop between the entrance and tube exit is influenced by the angle (b) of the inclined plane. This angle is dependent on the viscosity of the fluid.
  • #1
pippobaudo
9
0
Hello,

I have the following system (see enclosed figure): A viscous (non Newtonian) fluid at high temperature is going trough a tube at a known mass flow, at the exit there is an inclined plane at a given angle (b).
I would like to estimate in some way how the inclined plane at the exit influences the Pressure drop between the entrance and the tube exit. In addition i'd like to calculate how the pressure drop varies as a function of the angle (b) of the inclined plane.

Any help is appreciated, also If you could suggest some good books on viscous flow hydrodynamics.

Thanks guys,
Pippo
 
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  • #2
I don't understand why you (apparently) equate viscosity with non-Newtonian behavior.

Your figure is not attached, but the behavior of a viscous fluid leaving a constricted tube (a nozzle) is fairly straightforward in most cases. Streeter's "Fluid Mechanics" is a decent place to start.
 
  • #3
Hello and thanks for the reply,

well let's say that is a very viscous fluid which, in order to be fluidized, has to be heated to more than 100 Celsius.
I try to enclose again the figure, (I go to "manage Attachments" and upload) I hope It will be attached this time.

 

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  • #4
Ok, so the viscosity is a (strong) function of temperature. I wonder if that is more important than whatever nozzle geometry you have- what is the temperature of the fluid as it travels down the pipe and impinges on the plate? If the temperature becomes nonuniform (say the plate is cold but the fluid is hot), I would think the dominant effect would be due to the changes in viscosity.
 
  • #5
Hi, yes I think you are right, the temperature for fluidizing the medium is 120 Celsius.
However now I'd like to solve the problem assuming uniform viscosity, laminar flow and steady state conditions. In addition the temperature of the tube walls including the external object is assumed equal to that of the fluid.

I am thinking about finding the drag coefficient for this particular geometry and then estimate the force done on the flat surface, from this force will be possible to estimate (in some way...) a back pressure on the fluid so that the pressure drop between the entrance and tube exit will be estimated.

I didnt find yet this geometry among the drag coefficients for immersed bodies...
Thanks
 

Related to Pressure drop for viscous fluid in conducts with an obstacle at the outlet

1. What is pressure drop?

Pressure drop refers to the decrease in pressure that occurs in a fluid as it flows through a system. It is often caused by obstacles or restrictions in the flow path.

2. How does viscosity affect pressure drop?

Viscosity, or the thickness of a fluid, is a major factor in determining pressure drop. As viscosity increases, the resistance to flow also increases, resulting in a higher pressure drop.

3. How does an obstacle at the outlet affect pressure drop in a viscous fluid?

An obstacle at the outlet of a conduct can cause a significant increase in pressure drop for a viscous fluid. This is because the obstacle creates an obstruction to the flow, forcing the fluid to flow faster and creating a larger pressure drop.

4. What are some common methods for reducing pressure drop in conduct systems?

Some common methods for reducing pressure drop in conduct systems include increasing the diameter of the conduct, smoothing out rough surfaces, and using streamlined or tapered obstacles at the outlet.

5. How can pressure drop be calculated for a viscous fluid in a conduct with an obstacle at the outlet?

Pressure drop for a viscous fluid in a conduct with an obstacle at the outlet can be calculated using the Darcy-Weisbach equation, which takes into account factors such as fluid density, viscosity, and the geometry of the conduct and obstacle.

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